A community for students.
Here's the question you clicked on:
 0 viewing
Veneria
 3 years ago
does sqr(2/3) have a minimum or maximum point?
Veneria
 3 years ago
does sqr(2/3) have a minimum or maximum point?

This Question is Closed

slaaibak
 3 years ago
Best ResponseYou've already chosen the best response.0sqrt(2/3) is a single value. You sure you typed the correct question?

Veneria
 3 years ago
Best ResponseYou've already chosen the best response.0Yes. when using derivatives and you want to find whether the function has a min or max.

yrelhan4
 3 years ago
Best ResponseYou've already chosen the best response.3is that a double derivative of a fnxn?

yrelhan4
 3 years ago
Best ResponseYou've already chosen the best response.3so if at a pt double derivative is greater than 0 that pt is the minimum and if it is greater than 0 it is the maximum.

Veneria
 3 years ago
Best ResponseYou've already chosen the best response.0so it can be both( max and min) right?

yrelhan4
 3 years ago
Best ResponseYou've already chosen the best response.3sqrt(2/3) isnt a function. its a constant. it cannot have a min or max.

yrelhan4
 3 years ago
Best ResponseYou've already chosen the best response.3look. differentiate the fnxn you got once. put that equal to zero. plug the solution you got in the double derivative. then follow what i wrote earlier.

AravindG
 3 years ago
Best ResponseYou've already chosen the best response.0square root 2/3 is a constant function >it has no maximam or minimum the value always remains constant
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.