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slaaibak Group TitleBest ResponseYou've already chosen the best response.0
sqrt(2/3) is a single value. You sure you typed the correct question?
 one year ago

Rohangrr Group TitleBest ResponseYou've already chosen the best response.2
dw:1355749730751:dw
 one year ago

Veneria Group TitleBest ResponseYou've already chosen the best response.0
Yes. when using derivatives and you want to find whether the function has a min or max.
 one year ago

yrelhan4 Group TitleBest ResponseYou've already chosen the best response.3
is that a double derivative of a fnxn?
 one year ago

yrelhan4 Group TitleBest ResponseYou've already chosen the best response.3
so if at a pt double derivative is greater than 0 that pt is the minimum and if it is greater than 0 it is the maximum.
 one year ago

Veneria Group TitleBest ResponseYou've already chosen the best response.0
so it can be both( max and min) right?
 one year ago

yrelhan4 Group TitleBest ResponseYou've already chosen the best response.3
sqrt(2/3) isnt a function. its a constant. it cannot have a min or max.
 one year ago

yrelhan4 Group TitleBest ResponseYou've already chosen the best response.3
look. differentiate the fnxn you got once. put that equal to zero. plug the solution you got in the double derivative. then follow what i wrote earlier.
 one year ago

AravindG Group TitleBest ResponseYou've already chosen the best response.0
square root 2/3 is a constant function >it has no maximam or minimum the value always remains constant
 one year ago

AravindG Group TitleBest ResponseYou've already chosen the best response.0
dw:1355751027458:dw
 one year ago
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