anonymous
  • anonymous
A rocket travels 50 km vertically upward at a 90° angle from point A to point B. It then moves a distance of 50 km along the line segment BC, as shown below. What is the height of the rocket, at point C, from the ground? 90 km 75 km 80 km 85 km
Mathematics
schrodinger
  • schrodinger
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anonymous
  • anonymous
anonymous
  • anonymous
oh man i hated those... dont you ave to the tan cos sin things?
anonymous
  • anonymous
those are for angles I beleive...

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anonymous
  • anonymous
yea i just need the distance :;
anonymous
  • anonymous
well its probably a special triangle... a 90,45,45?
anonymous
  • anonymous
nope its not :l
anonymous
  • anonymous
its a 90,60,30...
anonymous
  • anonymous
so whats \[x \sqrt{2} = 50km\]
anonymous
  • anonymous
well i dont know ... uhmmm i forgot all that stuff hold on let me work
anonymous
  • anonymous
nvm its \[x \sqrt{3} = 50\]
anonymous
  • anonymous
oh ok
anonymous
  • anonymous
I have no idea how to solve that xd
anonymous
  • anonymous
I'm thinking the answer is 75
anonymous
  • anonymous
i think its aprox. 9.128709
anonymous
  • anonymous
were did you get 75 ? lol i went to myalgebra.com and typed in x square root 30 = 50 and clicked solve lol thats what it gave me
anonymous
  • anonymous
lol looking at the picture :D
anonymous
  • anonymous
lol xD well my answer is wrong i guess or myalgebra.com is wrong xD
anonymous
  • anonymous
think I'll go with 75... :d
anonymous
  • anonymous
thanks for the help :)
anonymous
  • anonymous
alright your welcome for the help i didnt really give... xD

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