poopsiedoodle
Simplify the following problem



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poopsiedoodle
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\[\Huge\left( x ^{1/2} \right)^{1/6}\]

poopsiedoodle
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I hate these so much

shubhamsrg
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what if i ask you (x^2)^3 ?

poopsiedoodle
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I'm going to guess that this is x^2/4

poopsiedoodle
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2/3*

shubhamsrg
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why you divided the powers? o.O

poopsiedoodle
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wat

anonymous
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\[\frac{1}{2}\times \frac{1}{6}=?\]

poopsiedoodle
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\[2/3.\] So, am I right about it being \[\Huge{x^{2/3}}\] ?

anonymous
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multiply fractions by multiplying straight across

poopsiedoodle
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oops. \[1/12\]

anhhuyalex
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So this is the general rule:
\[(x^m)^n=x^{mn}\]
So \[(x^{\frac{1}{2}})^{\frac{1}{6}}= x^{\frac{1}{2} \times \frac{1}{6}}\]