• anonymous
Is the serie $\sum_{n=0}^{\infty} (-1)^{n}\frac{ n+2 }{ 3^{n} }$ convergent or divergent? Calculate is't value. $\lim_{n \rightarrow \infty} \left| \left( \frac{ (-1)^{n+1}(n+3) }{ 3^{n+1} } \right)\left( \frac{ 3^{n} }{ (-1)^{n}(n+2) } \right) \right|$ $\frac{ 1 }{ 3 } \lim_{n \rightarrow \infty} \left| \frac{ n+3 }{n+2 } \right|=\frac{ 1 }{ 3 }$ $\frac{ 1 }{ 3 } < 1; Convergent$ But how do I calculate it's value?
Mathematics

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