experimentX 4 years ago Integrate: $\int_0^\infty {\ln x \over 1+x^2}dx$

1. hba

I cannot see latex :(

2. experimentX

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3. experimentX

it's pretty easy after you know it's value. If possible try without knowing the final results.

4. Zarkon

look at $\int_{1}^{\infty}\frac{\log(x)}{1+x^2}dx$ make the substitution $$x=\frac{1}{u}$$

5. hba

So 0 is the final result.

6. experimentX

yep