taydub10
sqrt x^25x+4=x3
solve the radical equation



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josiahh
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\[\sqrt(x^25x+4)=x3 ?\]

frx
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Is it this you mean?
\[\sqrt{x ^{2}5x+4}=x3\]

taydub10
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yes

frx
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Just square both sides then

josiahh
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square both sides and get: x^25x+4=(x3)^2
x^25x+4=x^26x+9
x=5