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pathosdebaterBest ResponseYou've already chosen the best response.0
Is this how it is supposed to look?
 one year ago

brazellnicole25Best ResponseYou've already chosen the best response.0
\[M \sin Bt+N \cos Bt=\sqrt{M^2+N^2} \sin (Bt+C)\]
 one year ago

pathosdebaterBest ResponseYou've already chosen the best response.0
Trying to solutions for the variable t, right?
 one year ago

brazellnicole25Best ResponseYou've already chosen the best response.0
\[M \sin Bt+N \cos Bt=\sqrt{M^2+N^2}\div \sqrt{M^2+N^2}timesM \sin Bt+N \cos Bt\]
 one year ago

brazellnicole25Best ResponseYou've already chosen the best response.0
I know I should also use the sum identity for the sine function. But, I'm stuck and have a blank on what to do next.
 one year ago

pathosdebaterBest ResponseYou've already chosen the best response.0
t = (1/B) cos^1
 one year ago
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