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brazellnicole25
Msin(Bt)+Ncos(Bt)=squareroot(M^2+N^2)sin(Bt+C)
Is this how it is supposed to look?
\[M \sin Bt+N \cos Bt=\sqrt{M^2+N^2} \sin (Bt+C)\]
Trying to solutions for the variable t, right?
\[M \sin Bt+N \cos Bt=\sqrt{M^2+N^2}\div \sqrt{M^2+N^2}timesM \sin Bt+N \cos Bt\]
I know I should also use the sum identity for the sine function. But, I'm stuck and have a blank on what to do next.
t = -(1/B) cos^-1