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anonymous
 4 years ago
Msin(Bt)+Ncos(Bt)=squareroot(M^2+N^2)sin(Bt+C)
anonymous
 4 years ago
Msin(Bt)+Ncos(Bt)=squareroot(M^2+N^2)sin(Bt+C)

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Is this how it is supposed to look?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[M \sin Bt+N \cos Bt=\sqrt{M^2+N^2} \sin (Bt+C)\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Trying to solutions for the variable t, right?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[M \sin Bt+N \cos Bt=\sqrt{M^2+N^2}\div \sqrt{M^2+N^2}timesM \sin Bt+N \cos Bt\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I know I should also use the sum identity for the sine function. But, I'm stuck and have a blank on what to do next.
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