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brazellnicole25

  • 2 years ago

Msin(Bt)+Ncos(Bt)=squareroot(M^2+N^2)sin(Bt+C)

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  1. pathosdebater
    • 2 years ago
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    Is this how it is supposed to look?

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  2. brazellnicole25
    • 2 years ago
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    \[M \sin Bt+N \cos Bt=\sqrt{M^2+N^2} \sin (Bt+C)\]

  3. pathosdebater
    • 2 years ago
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    Trying to solutions for the variable t, right?

  4. brazellnicole25
    • 2 years ago
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    \[M \sin Bt+N \cos Bt=\sqrt{M^2+N^2}\div \sqrt{M^2+N^2}timesM \sin Bt+N \cos Bt\]

  5. brazellnicole25
    • 2 years ago
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    I know I should also use the sum identity for the sine function. But, I'm stuck and have a blank on what to do next.

  6. pathosdebater
    • 2 years ago
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    t = -(1/B) cos^-1

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