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pathosdebater
 2 years ago
Best ResponseYou've already chosen the best response.0Is this how it is supposed to look?

brazellnicole25
 2 years ago
Best ResponseYou've already chosen the best response.0\[M \sin Bt+N \cos Bt=\sqrt{M^2+N^2} \sin (Bt+C)\]

pathosdebater
 2 years ago
Best ResponseYou've already chosen the best response.0Trying to solutions for the variable t, right?

brazellnicole25
 2 years ago
Best ResponseYou've already chosen the best response.0\[M \sin Bt+N \cos Bt=\sqrt{M^2+N^2}\div \sqrt{M^2+N^2}timesM \sin Bt+N \cos Bt\]

brazellnicole25
 2 years ago
Best ResponseYou've already chosen the best response.0I know I should also use the sum identity for the sine function. But, I'm stuck and have a blank on what to do next.

pathosdebater
 2 years ago
Best ResponseYou've already chosen the best response.0t = (1/B) cos^1
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