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anonymous
 3 years ago
Operations on Complex Numbers
anonymous
 3 years ago
Operations on Complex Numbers

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0simplify the expression

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Ok so start by rewrite \[\sqrt{10}=i \sqrt{10}\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Do you get that idea?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0yes I understand that i believe

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Do the same with sqrt(5)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0ok so its i\[\sqrt{5}\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1355782789409:dw

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Not really, the reason for why you take out the i is that you want the minus under the squareroot to disappear

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Do you know the definition of i?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0\[i=\sqrt{1}\] \[i ^{2}=1\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0well i know that i means the y on a plane and it is the imaginary part?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0That's also, kind of, correct when dealing with imaginary numbers the YX plane is called ImRe

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0So based on the definition of \[i=\sqrt{1}\] what's, for example \[\sqrt{7}\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0\[i \sqrt{10}(11+i \sqrt{5})\]=\[11i \sqrt{10}+i ^{2}\sqrt{10}\sqrt{5}= 11i \sqrt{10}\sqrt{50}\]
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