itsjustme_lol
Operations on Complex Numbers



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itsjustme_lol
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simplify the expression

frx
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Ok so start by rewrite \[\sqrt{10}=i \sqrt{10}\]

itsjustme_lol
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ok, im following

frx
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Do you get that idea?

itsjustme_lol
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yes I understand that i believe

frx
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Do the same with sqrt(5)

frx
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Then distribute

itsjustme_lol
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ok so its i\[\sqrt{5}\]

itsjustme_lol
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hang on

itsjustme_lol
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dw:1355782789409:dw

frx
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Not really, the reason for why you take out the i is that you want the minus under the squareroot to disappear

frx
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\[i \sqrt{5}\]

frx
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Do you know the definition of i?

frx
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\[i=\sqrt{1}\]
\[i ^{2}=1\]

itsjustme_lol
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well i know that i means the y on a plane and it is the imaginary part?

frx
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That's also, kind of, correct when dealing with imaginary numbers the YX plane is called ImRe

frx
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So based on the definition of \[i=\sqrt{1}\]
what's, for example \[\sqrt{7}\]

frx
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?

frx
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\[i \sqrt{10}(11+i \sqrt{5})\]=\[11i \sqrt{10}+i ^{2}\sqrt{10}\sqrt{5}= 11i \sqrt{10}\sqrt{50}\]