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itsjustme_lolBest ResponseYou've already chosen the best response.0
simplify the expression
 one year ago

frxBest ResponseYou've already chosen the best response.0
Ok so start by rewrite \[\sqrt{10}=i \sqrt{10}\]
 one year ago

itsjustme_lolBest ResponseYou've already chosen the best response.0
ok, im following
 one year ago

itsjustme_lolBest ResponseYou've already chosen the best response.0
yes I understand that i believe
 one year ago

itsjustme_lolBest ResponseYou've already chosen the best response.0
ok so its i\[\sqrt{5}\]
 one year ago

itsjustme_lolBest ResponseYou've already chosen the best response.0
dw:1355782789409:dw
 one year ago

frxBest ResponseYou've already chosen the best response.0
Not really, the reason for why you take out the i is that you want the minus under the squareroot to disappear
 one year ago

frxBest ResponseYou've already chosen the best response.0
Do you know the definition of i?
 one year ago

frxBest ResponseYou've already chosen the best response.0
\[i=\sqrt{1}\] \[i ^{2}=1\]
 one year ago

itsjustme_lolBest ResponseYou've already chosen the best response.0
well i know that i means the y on a plane and it is the imaginary part?
 one year ago

frxBest ResponseYou've already chosen the best response.0
That's also, kind of, correct when dealing with imaginary numbers the YX plane is called ImRe
 one year ago

frxBest ResponseYou've already chosen the best response.0
So based on the definition of \[i=\sqrt{1}\] what's, for example \[\sqrt{7}\]
 one year ago

frxBest ResponseYou've already chosen the best response.0
\[i \sqrt{10}(11+i \sqrt{5})\]=\[11i \sqrt{10}+i ^{2}\sqrt{10}\sqrt{5}= 11i \sqrt{10}\sqrt{50}\]
 one year ago
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