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itsjustme_lol

  • 3 years ago

Operations on Complex Numbers

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  1. itsjustme_lol
    • 3 years ago
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    simplify the expression

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  2. frx
    • 3 years ago
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    Ok so start by rewrite \[\sqrt{-10}=i \sqrt{10}\]

  3. itsjustme_lol
    • 3 years ago
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    ok, im following

  4. frx
    • 3 years ago
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    Do you get that idea?

  5. itsjustme_lol
    • 3 years ago
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    yes I understand that i believe

  6. frx
    • 3 years ago
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    Do the same with sqrt(-5)

  7. frx
    • 3 years ago
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    Then distribute

  8. itsjustme_lol
    • 3 years ago
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    ok so its i\[\sqrt{-5}\]

  9. itsjustme_lol
    • 3 years ago
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    hang on

  10. itsjustme_lol
    • 3 years ago
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    |dw:1355782789409:dw|

  11. frx
    • 3 years ago
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    Not really, the reason for why you take out the i is that you want the minus under the squareroot to disappear

  12. frx
    • 3 years ago
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    \[i \sqrt{5}\]

  13. frx
    • 3 years ago
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    Do you know the definition of i?

  14. frx
    • 3 years ago
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    \[i=\sqrt{-1}\] \[i ^{2}=-1\]

  15. itsjustme_lol
    • 3 years ago
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    well i know that i means the y on a plane and it is the imaginary part?

  16. frx
    • 3 years ago
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    That's also, kind of, correct when dealing with imaginary numbers the Y-X plane is called Im-Re

  17. frx
    • 3 years ago
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    So based on the definition of \[i=\sqrt{-1}\] what's, for example \[\sqrt{-7}\]

  18. frx
    • 3 years ago
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    ?

  19. frx
    • 3 years ago
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    \[i \sqrt{10}(11+i \sqrt{5})\]=\[11i \sqrt{10}+i ^{2}\sqrt{10}\sqrt{5}= 11i \sqrt{10}-\sqrt{50}\]

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