Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
 0 viewing
gabby817
Group Title
Please help me. A travel airline surveyed 950 business travelers 19% responded. What is the probability that more than 25% say that their travel was internal company visit
 one year ago
 one year ago
gabby817 Group Title
Please help me. A travel airline surveyed 950 business travelers 19% responded. What is the probability that more than 25% say that their travel was internal company visit
 one year ago
 one year ago

This Question is Open

liza2 Group TitleBest ResponseYou've already chosen the best response.0
you didn't provide enough info to answer this.
 one year ago

gabby817 Group TitleBest ResponseYou've already chosen the best response.0
Travel weekly International air transport association survey asked business travelers about their purpose for their most recent business, trip. 19% respond that it was for an internal company visit. Suppose950 business travelers are randomly selected. What is the probability that more than 25% of the business tracers say that their most recent business trip was an internal company visit
 one year ago

queelius Group TitleBest ResponseYou've already chosen the best response.0
This is probably a problem that can be solved more appropriately (and more effectively) using stats, but since I haven't taken stats in such a long time I don't feel inclined to solve it that way. I'm going to go with a pure probability (number of ways) approach  I apologize to anyone reading this ahead of time. Imagine a branching tree, where each node in the tree can go in one of two directions with probability p = 0.19 that they take the outbound edge for "most recent business trip was an internal company visit" and otherwise they take the other edge with probability (1p) = 0.81. If we do this for 950 people, and n of them took the p edge, and (950  n) took the (1p) edge, then the probability of that path through the tree is p^n * (1p)^(950n). A very low probability, to be sure, no matter what n is. So, now we want to figure out all the ways in which a path of n edges are the "p" edges, which is just (950 choose n) ways. So: (950 choose n) * [ p^n * (1p)^(950n) ] If we allow n to be a nonwhole number (thanks to various extensions to the factorial, this is possible), then we can choose n to be a fraction equal to 950 * 0.25 = 237.5. So, the final equation is: (950 choose 237.5) * p^237.5 * (1p)^(950  237.5) This will be a small number. I'm not sure it makes much sense, either. I think a more reasonably interpretation is to say, ok, we can't have 25% on the nose  a person can't be divided. So, find a close whole number approximation, e.g., 238 people. In fact, we also don't want 25% on the nose, but rather in the range of 24.5% to 25.5%, being sure to round to the nearest whole numbers for the endpoints > 233 to 242 people. So, sum over this, e.g.: [sum from n = 233 to n = 242] (950 choose n) * [ p^n * (1p)^(950n) ] I'm sure this is a terrible approach, and there are statistical approaches that will deal with this problem much more effectively.
 one year ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.