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AEB047

  • 3 years ago

How do you solve 3x^2+9xy+6x^2=(3x+6y)*w for w?

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  1. chaguanas
    • 3 years ago
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    Divide both sides by 3x+6y

  2. mathstudent55
    • 3 years ago
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    Since w is only on the right side multiplied by a factor, divide both sides by that factor

  3. AEB047
    • 3 years ago
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    done

  4. AEB047
    • 3 years ago
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    what do I do next?

  5. mathstudent55
    • 3 years ago
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    Now try to factor the numerator on the left. First divide it by three. The factor you divided by 3x + 6y can also be factored. A 3 comes out.

  6. AEB047
    • 3 years ago
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    how?

  7. AEB047
    • 3 years ago
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    Is it 3(x^2+3xy+2y^2)?

  8. AEB047
    • 3 years ago
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    over 6y?

  9. mathstudent55
    • 3 years ago
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    |dw:1355790864929:dw|

  10. mathstudent55
    • 3 years ago
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    Are you sure last term on original problem's left side is 6x^2 and not 6y^2?

  11. AEB047
    • 3 years ago
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    Yep. That would be a lot easier.

  12. AEB047
    • 3 years ago
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    I'm sure it is 6y.

  13. mathstudent55
    • 3 years ago
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    You have 6x^2. I asked you if it's 6y^2, and you say you're sure it's 6y. Which is it: 6x^2 6y^2 6y

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