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abz_techBest ResponseYou've already chosen the best response.0
\[\int\limits\limits_{0}^{1} \frac{ x+1 }{ x ^{2}+6x+5 }dx\]
 one year ago

Mimi_x3Best ResponseYou've already chosen the best response.1
\[x^2+ 6x + 5 = (x+3)^2 (3)^2 + 5 = (x+3)^2 9 +5 = (x+3)^2 1 \] \[\int\limits \frac{x+1}{(x+3)^{2}1} \]
 one year ago

Mimi_x3Best ResponseYou've already chosen the best response.1
Wait. \[\frac{x+1}{(x+5)(x+1)} = \frac{A}{(x+5)} +\frac{B}{(x+1)} \] Better now. :D
 one year ago

Mimi_x3Best ResponseYou've already chosen the best response.1
For A: \(x= 5\) \[\frac{(5+1)}{(5+1)} =\frac{4}{4}=1 \]
 one year ago

HeroBest ResponseYou've already chosen the best response.1
Aren't you forgetting something @Mimi_x3 ?
 one year ago

Mimi_x3Best ResponseYou've already chosen the best response.1
For B: \(x= 1\) => \(0\) What am I forgetting?
 one year ago

HeroBest ResponseYou've already chosen the best response.1
\[\frac{(x+1)}{(x+5)(x+1)} = \frac{1}{x+5}\]
 one year ago

Mimi_x3Best ResponseYou've already chosen the best response.1
There is something wrong.
 one year ago

abz_techBest ResponseYou've already chosen the best response.0
isn't u's and du/dx supposed to come into play about now 0_o?
 one year ago

HeroBest ResponseYou've already chosen the best response.1
\[\int\limits_{0}^{1}(x+5)^{1}dx\]
 one year ago

Mimi_x3Best ResponseYou've already chosen the best response.1
I was right anyway :P just went the long way.
 one year ago

HeroBest ResponseYou've already chosen the best response.1
Ya, exactly. You're so silly :P
 one year ago

Mimi_x3Best ResponseYou've already chosen the best response.1
That doesn't work hero, u = x+5
 one year ago

HeroBest ResponseYou've already chosen the best response.1
I can make u = x + 5 if I want or not. It doesn't matter. It will still work.
 one year ago

abz_techBest ResponseYou've already chosen the best response.0
how would u solve (x+5)^1
 one year ago

winterfezBest ResponseYou've already chosen the best response.0
no i guess that does not work
 one year ago

Mimi_x3Best ResponseYou've already chosen the best response.1
\[\int\limits\frac{1}{x+5}dx \] \[u = x+5 => \frac{du}{dx} = 1 => du = dx \] \[\int\limits\frac{1}{u} du = \ln(x+5) + C\] @hero: writing in that form won't work.
 one year ago

HeroBest ResponseYou've already chosen the best response.1
I don't need @mimi_x3 ( a kid) to tell me things, lol
 one year ago

winterfezBest ResponseYou've already chosen the best response.0
@hero right, is absolute value for ln
 one year ago

Mimi_x3Best ResponseYou've already chosen the best response.1
I am not a kid!! It's the truth it won't work in the form; of if you want to use that retarded formula.
 one year ago

abz_techBest ResponseYou've already chosen the best response.0
hero how would u go about doing \[\int\limits_{0}^{1} (x+5)^{1}\]
 one year ago

Mimi_x3Best ResponseYou've already chosen the best response.1
Using that form; wont get you anyway; and get lost.
 one year ago

abz_techBest ResponseYou've already chosen the best response.0
fine mimi, can u tell me your way =/?
 one year ago

HeroBest ResponseYou've already chosen the best response.1
She already did. @winterfez, also provided some good steps.
 one year ago

Mimi_x3Best ResponseYou've already chosen the best response.1
i typed up the solution!!! scroll upp!!
 one year ago

HeroBest ResponseYou've already chosen the best response.1
I think I deserve a medal for pointing @mimi_x3 in the right direction.
 one year ago

abz_techBest ResponseYou've already chosen the best response.0
then with the limits would i be ln 6  ln 5?
 one year ago

Mimi_x3Best ResponseYou've already chosen the best response.1
Well, first I was not wrong,I just went the long way. I would have gotten the right anwer without your input. Secondly, can you please show us how you would integrate \[\int\limits(x+5)^{1} dx\]
 one year ago

Mimi_x3Best ResponseYou've already chosen the best response.1
Lol, because it's impossible :)
 one year ago

Mimi_x3Best ResponseYou've already chosen the best response.1
Me want a medal as well!
 one year ago
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