Open study

is now brainly

With Brainly you can:

  • Get homework help from millions of students and moderators
  • Learn how to solve problems with step-by-step explanations
  • Share your knowledge and earn points by helping other students
  • Learn anywhere, anytime with the Brainly app!

A community for students.

What is the equation of the axis of symmetry of the quadratic equation y = 2(x – 4)2 + 7?

I got my questions answered at in under 10 minutes. Go to now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Join Brainly to access

this expert answer


To see the expert answer you'll need to create a free account at Brainly

Do you mean\[y=2(x-4)^{2}+7\]
\(\large\text{if you help me with this, I will love you forever.}\) And yes.

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

So you know that vertex form is \[y=a(x-h)^{2}+k\] and that (h,k) is the same as (x,y) right?
Well the axis of symmetry is just x. And since x is 4 in this, the equation of the axis of symmetry is x=4
Do you understand?
Kinda. The part I don't get is the (x-h)^2 part. I forgot the rule for squaring things inside of parentheses ._.
oh wait. I feel kinda dumb now.
don't even need that. Sorry for being a dingus.
So do you understand?
Yeah \(\Huge{:3}\)
Ok ^-^

Not the answer you are looking for?

Search for more explanations.

Ask your own question