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poopsiedoodle

  • 2 years ago

What is the equation of the axis of symmetry of the quadratic equation y = 2(x – 4)2 + 7?

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  1. Mathhelp346
    • 2 years ago
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    Do you mean\[y=2(x-4)^{2}+7\]

  2. poopsiedoodle
    • 2 years ago
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    \(\large\text{if you help me with this, I will love you forever.}\) And yes.

  3. Mathhelp346
    • 2 years ago
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    Ok

  4. Mathhelp346
    • 2 years ago
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    So you know that vertex form is \[y=a(x-h)^{2}+k\] and that (h,k) is the same as (x,y) right?

  5. poopsiedoodle
    • 2 years ago
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    Yes.

  6. Mathhelp346
    • 2 years ago
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    Well the axis of symmetry is just x. And since x is 4 in this, the equation of the axis of symmetry is x=4

  7. Mathhelp346
    • 2 years ago
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    Do you understand?

  8. poopsiedoodle
    • 2 years ago
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    Kinda. The part I don't get is the (x-h)^2 part. I forgot the rule for squaring things inside of parentheses ._.

  9. poopsiedoodle
    • 2 years ago
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    oh wait. I feel kinda dumb now.

  10. poopsiedoodle
    • 2 years ago
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    don't even need that. Sorry for being a dingus.

  11. Mathhelp346
    • 2 years ago
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    o.O

  12. Mathhelp346
    • 2 years ago
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    So do you understand?

  13. poopsiedoodle
    • 2 years ago
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    Yeah \(\Huge{:3}\)

  14. Mathhelp346
    • 2 years ago
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    Ok ^-^

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