Dido525
Evaluate the limit:



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Dido525
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dw:1355798329824:dw

Dido525
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I got to the point where I transformed it to:
dw:1355798387822:dw

Zarkon
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\[\lim_{x\to\infty}\left(1+\frac{a}{x}\right)^{bx}=e^{ab}\]

Dido525
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Well... I would like to use L'hospital's rule...

Zarkon
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then use it :)

Dido525
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I can't :( . I am stuck.

Zarkon
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differentiate the top and the bottom...what is the holdup

Dido525
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dw:1355798464643:dw

Dido525
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The problem is if I keep using L'hospital's rule it's not really going to help...

Dido525
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I still keep getting 0/0 .

Zarkon
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why do you have a 4

Dido525
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Isn't the derivative of 1/(2x) 1/(4x^2) ?

Zarkon
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no

Dido525
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That could be my mistake.

Zarkon
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\[\frac{d}{dx}\frac{1}{2x}=\frac{1}{2x^2}\]

Dido525
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Right... :P .

Zarkon
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you should be able to cancel out the \(x^2\)'s

Zarkon
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dw:1355798716195:dw

Zarkon
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dw:1355798750796:dw

Dido525
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Thanks :) . I did a lot more work but got it :) .

Zarkon
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good