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Dido525

  • 3 years ago

Evaluate the limit:

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  1. Dido525
    • 3 years ago
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    |dw:1355798329824:dw|

  2. Dido525
    • 3 years ago
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    I got to the point where I transformed it to: |dw:1355798387822:dw|

  3. Zarkon
    • 3 years ago
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    \[\lim_{x\to\infty}\left(1+\frac{a}{x}\right)^{bx}=e^{ab}\]

  4. Dido525
    • 3 years ago
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    Well... I would like to use L'hospital's rule...

  5. Zarkon
    • 3 years ago
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    then use it :)

  6. Dido525
    • 3 years ago
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    I can't :( . I am stuck.

  7. Zarkon
    • 3 years ago
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    differentiate the top and the bottom...what is the holdup

  8. Dido525
    • 3 years ago
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    |dw:1355798464643:dw|

  9. Dido525
    • 3 years ago
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    The problem is if I keep using L'hospital's rule it's not really going to help...

  10. Dido525
    • 3 years ago
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    I still keep getting 0/0 .

  11. Zarkon
    • 3 years ago
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    why do you have a 4

  12. Dido525
    • 3 years ago
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    Isn't the derivative of 1/(2x) -1/(4x^2) ?

  13. Zarkon
    • 3 years ago
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    no

  14. Dido525
    • 3 years ago
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    That could be my mistake.

  15. Zarkon
    • 3 years ago
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    \[\frac{d}{dx}\frac{1}{2x}=\frac{-1}{2x^2}\]

  16. Dido525
    • 3 years ago
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    Right... :P .

  17. Zarkon
    • 3 years ago
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    you should be able to cancel out the \(x^2\)'s

  18. Zarkon
    • 3 years ago
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    |dw:1355798716195:dw|

  19. Zarkon
    • 3 years ago
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    |dw:1355798750796:dw|

  20. Dido525
    • 3 years ago
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    Thanks :) . I did a lot more work but got it :) .

  21. Zarkon
    • 3 years ago
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    good

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