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Dido525

Evaluate the limit:

  • one year ago
  • one year ago

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  1. Dido525
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    |dw:1355798329824:dw|

    • one year ago
  2. Dido525
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    I got to the point where I transformed it to: |dw:1355798387822:dw|

    • one year ago
  3. Zarkon
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    \[\lim_{x\to\infty}\left(1+\frac{a}{x}\right)^{bx}=e^{ab}\]

    • one year ago
  4. Dido525
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    Well... I would like to use L'hospital's rule...

    • one year ago
  5. Zarkon
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    then use it :)

    • one year ago
  6. Dido525
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    I can't :( . I am stuck.

    • one year ago
  7. Zarkon
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    differentiate the top and the bottom...what is the holdup

    • one year ago
  8. Dido525
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    |dw:1355798464643:dw|

    • one year ago
  9. Dido525
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    The problem is if I keep using L'hospital's rule it's not really going to help...

    • one year ago
  10. Dido525
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    I still keep getting 0/0 .

    • one year ago
  11. Zarkon
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    why do you have a 4

    • one year ago
  12. Dido525
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    Isn't the derivative of 1/(2x) -1/(4x^2) ?

    • one year ago
  13. Zarkon
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    no

    • one year ago
  14. Dido525
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    That could be my mistake.

    • one year ago
  15. Zarkon
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    \[\frac{d}{dx}\frac{1}{2x}=\frac{-1}{2x^2}\]

    • one year ago
  16. Dido525
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    Right... :P .

    • one year ago
  17. Zarkon
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    you should be able to cancel out the \(x^2\)'s

    • one year ago
  18. Zarkon
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    |dw:1355798716195:dw|

    • one year ago
  19. Zarkon
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    |dw:1355798750796:dw|

    • one year ago
  20. Dido525
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    Thanks :) . I did a lot more work but got it :) .

    • one year ago
  21. Zarkon
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    good

    • one year ago
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