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DoritosHero
 2 years ago
Best ResponseYou've already chosen the best response.1Yes that would be the case if pi was in the numerator, but I think you said pi was in the denominator though?

4thief
 2 years ago
Best ResponseYou've already chosen the best response.0\[f(t)=20[1\cos^2(\frac{ t }{ 1000\pi })\] like that ^

4thief
 2 years ago
Best ResponseYou've already chosen the best response.0\[\frac{ \sin(\frac{ x }{ 500\pi }) }{ 50\pi }\] is this your answer?

DoritosHero
 2 years ago
Best ResponseYou've already chosen the best response.1\[f(t) = 20  20\cos ^{2}(t/(1000\pi))\] \[f'(t) = 0  20 * 2\cos (t/(1000\pi)) * \sin (t/(1000\pi)) * (1/(1000\pi))\] \[f`(t) = 20/1000\pi * 2\cos(t/1000\pi)*\sin(t/1000\pi)\] Use identity sin (2x) = 2sinxcosx \[f'(t) = 1/50\pi * \sin (2*t/1000\pi)\]

4thief
 2 years ago
Best ResponseYou've already chosen the best response.0that acually looks right to me. ^

DoritosHero
 2 years ago
Best ResponseYou've already chosen the best response.1You can also check your answers by punching the equations into wolframalpha.com

DoritosHero
 2 years ago
Best ResponseYou've already chosen the best response.1No problem, good luck!
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