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Dido525
 2 years ago
Best ResponseYou've already chosen the best response.0I thought I could use substitution but I can't ...

winterfez
 2 years ago
Best ResponseYou've already chosen the best response.0is this right? \[\int\limits_{0}^{4}\frac{ x }{ \sqrt{1+2x} }\]

Mimi_x3
 2 years ago
Best ResponseYou've already chosen the best response.4\( u = 1+ 2x => du/dx = 2\) \( 1+2x = u => 2x = u1 => x = (u1)/2 \)

Dido525
 2 years ago
Best ResponseYou've already chosen the best response.0I got to that step. Then I got stuck :P .

Mimi_x3
 2 years ago
Best ResponseYou've already chosen the best response.4Maybe:\[\int\limits\frac{x}{\sqrt{1+2x}} dx => \int\limits \frac{(u1)/2}{\sqrt{u}} *2du \int\limits\frac{u1}{2} *\frac{1}{\sqrt{u}} 2du => 2\int\limits\frac{u1}{2} *\frac{1}{\sqrt{u}} \]

eliassaab
 2 years ago
Best ResponseYou've already chosen the best response.1Here what wolfram alpha gave

Mimi_x3
 2 years ago
Best ResponseYou've already chosen the best response.4Would my step work tho?

zepdrix
 2 years ago
Best ResponseYou've already chosen the best response.1@Dido525 do you understand what mimi did? those are the correct steps to take.

Dido525
 2 years ago
Best ResponseYou've already chosen the best response.0Yeah I actually do. I just need to process it.

Dido525
 2 years ago
Best ResponseYou've already chosen the best response.0@Mimi_x3 : Wouldn't you write du/2 instead of 2*du ?

Dido525
 2 years ago
Best ResponseYou've already chosen the best response.0Because we said du/2 was dx.

Mimi_x3
 2 years ago
Best ResponseYou've already chosen the best response.4Yeah typo lol sorry! that was where i went wrong :(

Dido525
 2 years ago
Best ResponseYou've already chosen the best response.0So so far I have: \[\frac{ 1 }{ 4 }\int\limits_{1}^{9} \frac{ u1 }{ \sqrt{u} } du\]

Mimi_x3
 2 years ago
Best ResponseYou've already chosen the best response.4integrate it; then don't forget to sub back in \(u\)
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