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Dido525Best ResponseYou've already chosen the best response.0
I thought I could use substitution but I can't ...
 one year ago

winterfezBest ResponseYou've already chosen the best response.0
is this right? \[\int\limits_{0}^{4}\frac{ x }{ \sqrt{1+2x} }\]
 one year ago

Mimi_x3Best ResponseYou've already chosen the best response.3
\( u = 1+ 2x => du/dx = 2\) \( 1+2x = u => 2x = u1 => x = (u1)/2 \)
 one year ago

Dido525Best ResponseYou've already chosen the best response.0
I got to that step. Then I got stuck :P .
 one year ago

Mimi_x3Best ResponseYou've already chosen the best response.3
Maybe:\[\int\limits\frac{x}{\sqrt{1+2x}} dx => \int\limits \frac{(u1)/2}{\sqrt{u}} *2du \int\limits\frac{u1}{2} *\frac{1}{\sqrt{u}} 2du => 2\int\limits\frac{u1}{2} *\frac{1}{\sqrt{u}} \]
 one year ago

eliassaabBest ResponseYou've already chosen the best response.1
Here what wolfram alpha gave
 one year ago

Mimi_x3Best ResponseYou've already chosen the best response.3
Would my step work tho?
 one year ago

zepdrixBest ResponseYou've already chosen the best response.1
@Dido525 do you understand what mimi did? those are the correct steps to take.
 one year ago

Dido525Best ResponseYou've already chosen the best response.0
Yeah I actually do. I just need to process it.
 one year ago

Dido525Best ResponseYou've already chosen the best response.0
@Mimi_x3 : Wouldn't you write du/2 instead of 2*du ?
 one year ago

Dido525Best ResponseYou've already chosen the best response.0
Because we said du/2 was dx.
 one year ago

Mimi_x3Best ResponseYou've already chosen the best response.3
Yeah typo lol sorry! that was where i went wrong :(
 one year ago

Dido525Best ResponseYou've already chosen the best response.0
So so far I have: \[\frac{ 1 }{ 4 }\int\limits_{1}^{9} \frac{ u1 }{ \sqrt{u} } du\]
 one year ago

Mimi_x3Best ResponseYou've already chosen the best response.3
integrate it; then don't forget to sub back in \(u\)
 one year ago
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