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|dw:1355802290129:dw|

I thought I could use substitution but I can't ...

is this right?
\[\int\limits_{0}^{4}\frac{ x }{ \sqrt{1+2x} }\]

yep :) .

put u= 1 + 2 x

\( u = 1+ 2x => du/dx = 2\)
\( 1+2x = u => 2x = u-1 => x = (u-1)/2 \)

I got to that step. Then I got stuck :P .

Would my step work tho?

Yeah I actually do. I just need to process it.

Because we said du/2 was dx.

Oh yes :o good call.

Yeah typo lol
sorry! that was where i went wrong :(

It's okay :) .

So so far I have:
\[\frac{ 1 }{ 4 }\int\limits_{1}^{9} \frac{ u-1 }{ \sqrt{u} } du\]

then break it up!

Ohh... Right :P .

integrate it; then don't forget to sub back in \(u\)

Thanks! :) .

:)