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Idealist
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Let f"(x)=4x^32x and let f(x) have critical values 1, 0, and 1. Determine which critical values give a relative maximum.
 one year ago
 one year ago
Idealist Group Title
Let f"(x)=4x^32x and let f(x) have critical values 1, 0, and 1. Determine which critical values give a relative maximum.
 one year ago
 one year ago

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dtran20 Group TitleBest ResponseYou've already chosen the best response.0
put those critical values into second derivative to find concave up or down. Concave down means max, concave down means min
 one year ago

Idealist Group TitleBest ResponseYou've already chosen the best response.0
So is 1 the answer?
 one year ago

dtran20 Group TitleBest ResponseYou've already chosen the best response.0
what's the definition of concave up and concave down?
 one year ago

Idealist Group TitleBest ResponseYou've already chosen the best response.0
Concave up means increasing where concave down means decreasing. So to find the maximum, you plug each critical values into the function to see which value gives you the greatest number, right?
 one year ago

dtran20 Group TitleBest ResponseYou've already chosen the best response.0
i meant to said f''[x]>0 means what? concave up or down? f''[x]<0 means what? up or down? f''[x]=0 means what?
 one year ago
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