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Idealist
 2 years ago
Let f"(x)=4x^32x and let f(x) have critical values 1, 0, and 1. Determine which critical values give a relative maximum.
Idealist
 2 years ago
Let f"(x)=4x^32x and let f(x) have critical values 1, 0, and 1. Determine which critical values give a relative maximum.

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dtran20
 2 years ago
Best ResponseYou've already chosen the best response.0put those critical values into second derivative to find concave up or down. Concave down means max, concave down means min

dtran20
 2 years ago
Best ResponseYou've already chosen the best response.0what's the definition of concave up and concave down?

Idealist
 2 years ago
Best ResponseYou've already chosen the best response.0Concave up means increasing where concave down means decreasing. So to find the maximum, you plug each critical values into the function to see which value gives you the greatest number, right?

dtran20
 2 years ago
Best ResponseYou've already chosen the best response.0i meant to said f''[x]>0 means what? concave up or down? f''[x]<0 means what? up or down? f''[x]=0 means what?
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