anonymous
  • anonymous
Which conic section does the equation attached describe? A. Circle B. Ellipse C. Parabola D. Hyperbola **my answer: B. ellipse is that right? =)
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
zepdrix
  • zepdrix
\[\huge \left(\frac{x}{a}\right)^2+\left(\frac{y}{b}\right)^2=1\] See the addition sign between them? Hmm I don't think that quite matches what we're looking for.
anonymous
  • anonymous
Hyperbola has form \[\frac{(x-h)^2}{a}+\frac{(y-k)^2}{b}=1\]

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anonymous
  • anonymous
ohhh okay so then I'm not too sure :(
zepdrix
  • zepdrix
That is the standard form of an ellipse* the one i posted before. Sorry my broswer really screwy :c grr
zepdrix
  • zepdrix
no mat :O don't confuse heart. Click the picture for the function, don't look at what I posted.
anonymous
  • anonymous
ohhh okay hahaa :P wait so I'm confused... what is this then?? :/
zepdrix
  • zepdrix
It's a hyperbola... as anhuya said :O
zepdrix
  • zepdrix
Oh she posted the wrong sign between them I think.. ugh sec lemme look it up XD
anonymous
  • anonymous
ohh i see :) it follows that format... :)
anonymous
  • anonymous
ok :) so what is it then??? :/
anonymous
  • anonymous
Sorry everyone, mistype Hyperbola form is \[\frac{(x-h)^2}{a^2}-\frac{(y-k)^2}{b^2}=1\]
zepdrix
  • zepdrix
I find these a little confusing because of all the extra numbers they throw at you. The -1 in x -1 just represents a horizontal shift to the right 1 unit. It doesn't affect the SHAPE of the graph at all. So I would recommend ignoring data like that. It might help you to see what's going on. The function essentially looks something like this,\[\huge \left(\frac{x}{a}\right)^2-\left(\frac{y}{b}\right)^2=1\]
anonymous
  • anonymous
okay, so i need to find the one that follows that format?
zepdrix
  • zepdrix
Yah c:
zepdrix
  • zepdrix
It might appear in your book as anhuya posted it.
anonymous
  • anonymous
okay, so this is a hyperbola? :/
anonymous
  • anonymous
like @anhhuyalex said?
anonymous
  • anonymous
or wrote above?
zepdrix
  • zepdrix
yah c: hyperbola.
anonymous
  • anonymous
okay!!! thank youu :)
anonymous
  • anonymous
its hyperbola i din't look ur post
anonymous
  • anonymous
haha okay thanks :)

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