anonymous
  • anonymous
help me to sketch graph for this question.. f(x)=(2/3)x^3+(5/2)x^2-3x?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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Goten77
  • Goten77
using 1st 2nd derivative test? or just a basic out line? or how much detail we talking?
Goten77
  • Goten77
XD i cant show work/answer until i kno how much of the graph u wanna kno *how accurate*
anonymous
  • anonymous
i don't know because the question juz ask sketch the graph of f(x)

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anonymous
  • anonymous
i think it abt first derivative bcause the first quest is about to differentiate..
Goten77
  • Goten77
k then
Goten77
  • Goten77
|dw:1355813735819:dw|
Goten77
  • Goten77
|dw:1355813846026:dw|
Goten77
  • Goten77
|dw:1355813889138:dw|
Goten77
  • Goten77
|dw:1355813967982:dw|
Goten77
  • Goten77
|dw:1355814013821:dw|
Goten77
  • Goten77
|dw:1355814046241:dw|
Goten77
  • Goten77
|dw:1355814112490:dw|
Goten77
  • Goten77
ya follow me?
anonymous
  • anonymous
yes....
Goten77
  • Goten77
k well domain is all reals...so is range and y(-3) = local max while y(1/2)= local min according to the 1st der test
Goten77
  • Goten77
um according to end behaviors we know that it starts in the bottom left quadrant and goes to the top right quadrant...
Goten77
  • Goten77
the x andy intercepts.. well usually they dont ask for those but i can do those 2
Goten77
  • Goten77
|dw:1355814855667:dw|
Goten77
  • Goten77
|dw:1355814960639:dw|
Goten77
  • Goten77
|dw:1355815097994:dw| that gets rounded to -4.6 and 1
Goten77
  • Goten77
but then -3 and 1/2 are pluged into original so we know those values of the original graph and where to graph.... f(-3)=13.5 f(1/2)=-.8
Goten77
  • Goten77
now with all that i get something like this |dw:1355815442995:dw|
Goten77
  • Goten77
as for concavity... XD not sure if u want 2nd derivative test to but.... i can do if it its required
anonymous
  • anonymous
oh no need..i think it juz want first derivative...thanks a lot ya...coz i get it now..
Goten77
  • Goten77
hmm k thats all that matters... and i didnt even explain side steps XD....
anonymous
  • anonymous
o its ok...i appreciate that...thanks..

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