help me to solve this question... Find the total area between the curve y=1-x^2, and the x-axis over the interval (0,2)...

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you have to integrate the given curve's equation in the interval (0,2) \[\int\limits_{0}^{2}1-x^2 = (2-0) + (-8/3 + 0) = 2 - 8/3 = -2/3\] Since are cannot be negative, area = 2/3 sq.units

sorry I'm little confused while typing equations on OpenStudy..so I've been a little late in answering

oo its ok..the working just like that AbhimanyuPudi ?

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