hba
  • hba
Checking my answers if f(x)=x^3-9x^2+15x+3 What is the relative maxima ?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
hba
  • hba
I got 10.
anonymous
  • anonymous
Really??
hba
  • hba
Yeah really.

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More answers

anonymous
  • anonymous
It will be right as it is calculated by the Great @hba ha ha ha..
hba
  • hba
Thanks.
hba
  • hba
I have more question to get checked can i ask here or in a new post.
anonymous
  • anonymous
I don't know how to solve these types of questions.. Can you teach me how to solve it..??
hba
  • hba
@waterineyes Ha Ha Ha Nice joke,first let me ask my questions.
anonymous
  • anonymous
First, we will take derivative.. Right??
hba
  • hba
Yeah.
anonymous
  • anonymous
So wait, I am doing it..
hba
  • hba
okay :(
anonymous
  • anonymous
f'(x) = 3x^2 - 18x + 15
sirm3d
  • sirm3d
there are two extrema, 1 relative maximum and 1 relative minimum.
anonymous
  • anonymous
Should I factorize it??
hba
  • hba
put f'(x)=0
anonymous
  • anonymous
Yes I mean the same..
hba
  • hba
Then the answer is yes
anonymous
  • anonymous
\[x^2 - 6x + 5 = 0 \implies (x - 5)(x - 1) = 0\]
anonymous
  • anonymous
x = 5 and x = 1
hba
  • hba
Yes you are right
hba
  • hba
Now put 1 in the orignal equation.
anonymous
  • anonymous
Why not 5 ??
hba
  • hba
Because we are finding the relative maxima
anonymous
  • anonymous
f(1) = 10
sirm3d
  • sirm3d
oooh, i misread the problem. relative maxima.
hba
  • hba
Correct.
anonymous
  • anonymous
So, we have to put smaller value??
hba
  • hba
Yes.
anonymous
  • anonymous
Just checking your answer.. Ha ha ha..
anonymous
  • anonymous
Now don't say, to find relative minima, we will put 5..
hba
  • hba
|dw:1355817149046:dw|
hba
  • hba
@waterineyes Check these two questions.
anonymous
  • anonymous
How to solve these now??
hba
  • hba
I got f'(x)=e in both the cases.
hba
  • hba
And f''(x)=1/e for 1st and f''(x)=e in the 2nd one.
hba
  • hba
So i am right ?
anonymous
  • anonymous
Are you sure it is e ??
hba
  • hba
Pretty sure Because i did this one like 100 times when i was in High school
anonymous
  • anonymous
You have used division rule here??
hba
  • hba
U/V form.
anonymous
  • anonymous
For first : \[f'(x) = \frac{1 - \ln(x)}{x^2}\]
hba
  • hba
Wait lemme check.
anonymous
  • anonymous
Take your time..
hba
  • hba
Yeah right
hba
  • hba
@waterineyes ?
anonymous
  • anonymous
Who is right??
hba
  • hba
The most intelligent @waterineyes
anonymous
  • anonymous
Not intelligent as you @hba
anonymous
  • anonymous
Now, find the second derivative..
hba
  • hba
Ha Ha Ha Yeah wait.
hba
  • hba
I am getting something,which looks extremly wrong :/
hba
  • hba
@waterineyes Here you go \[f''(x)=-x-2x+2lnx/x^4\] I kow it's wrong :/
anonymous
  • anonymous
Sorry busy helping other person..
anonymous
  • anonymous
Now I think, if it was e then it will be simpler..
anonymous
  • anonymous
Wait, let me check..
hba
  • hba
ok
anonymous
  • anonymous
You can add first two terms in the numerator..
hba
  • hba
Yeah i can add them so, \[f''(x)=-3x+2lnx/x^2\]
hba
  • hba
@waterineyes So ?
hba
  • hba
@waterineyes Ansoo kahan ho tum ?
hba
  • hba
@waterineyes Answer tau sahi hai mera,Is ki working mushkil hai :/
anonymous
  • anonymous
Now what to do next??
anonymous
  • anonymous
I had a guest in home so busy there.. Sorry, let us now work together..
anonymous
  • anonymous
There??
hba
  • hba
yeah
hba
  • hba
@waterineyes Where should i continue ?
anonymous
  • anonymous
What we will do next after finding second derivative?? To find extreme value..
hba
  • hba
put it equal to 0
anonymous
  • anonymous
\[2 \ln(x) = 3x\]
anonymous
  • anonymous
Where are we going?? Is that right??
hba
  • hba
i think we should skip these lol,I am pretty sure about my answers :) Do you know what is a stationary point ?
anonymous
  • anonymous
The point which is stationary is called Stationary Point, that's it..!!!
hba
  • hba
So, if f(x)=ln(1+x^2) What will be the stationary point ?
anonymous
  • anonymous
I think I should go now.. Ha ha ha.. Seriously, don't know..
hba
  • hba
Gurpreet :/ Chalo Bye.

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