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suneja

  • 3 years ago

Consider a regular polygon of p sides. The number of values of p for which the polygon will have angles whose values in degrees can be expressed in integers? A. 24 B. 23 C. 22 D. 20 E. 21

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  1. Kainui
    • 3 years ago
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    Try making a general formula for the sides of a regular polygon from pictures. A useful hint would be, remember that you can make any regular polygon into a bunch of equal triangles and the center contains a full 360 degrees and all triangles have 180 degrees.

  2. matricked
    • 3 years ago
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    it can be the number of factors 360 will have and its 22 (leaving 0 and 360)

  3. shubhamsrg
    • 3 years ago
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    yep..22 seems correct to me as well..

  4. matricked
    • 3 years ago
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    so is C the answer

  5. Kainui
    • 3 years ago
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    |dw:1355825287861:dw|

  6. matricked
    • 3 years ago
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    see each int angle of regular poly gon is given by 180 -(360/n)

  7. suneja
    • 3 years ago
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    ya i gt the formula thanks all:)

  8. Kainui
    • 3 years ago
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    |dw:1355825460643:dw|

  9. Kainui
    • 3 years ago
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    p*180-360=p*angle

  10. Kainui
    • 3 years ago
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    You can forget a formula, but if you can figure it out like this, you can do it on the test.

  11. suneja
    • 3 years ago
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    @Kainui thanks

  12. ParthKohli
    • 3 years ago
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    \(\dfrac{180(n - 2)}{n}\) is the measure of an angle in a regular polygon. So, you can always test the choices ;-)

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