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kinda silly but
lim y=sin(x)
x> infinity
this would be 0 since that occurs most in a given period
and
lim y=cos(x)
x>inifity
is 1 because that occurs most ina period...
but what would be
limit y=tan(x)
x> infinity ???
would it be undefined because you can take each individual limit and get
1/0= undefined?
 one year ago
 one year ago
kinda silly but lim y=sin(x) x> infinity this would be 0 since that occurs most in a given period and lim y=cos(x) x>inifity is 1 because that occurs most ina period... but what would be limit y=tan(x) x> infinity ??? would it be undefined because you can take each individual limit and get 1/0= undefined?
 one year ago
 one year ago

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shubhamsrgBest ResponseYou've already chosen the best response.0
lim x>inf for all sinx cosx and tanx are undefined..
 one year ago

shubhamsrgBest ResponseYou've already chosen the best response.0
why you say it'll be 0 or 1 ? o.O
 one year ago

Goten77Best ResponseYou've already chosen the best response.0
because thats what occurs most ina period... those are true fax
 one year ago

shubhamsrgBest ResponseYou've already chosen the best response.0
i meant to @Goten77
 one year ago

shubhamsrgBest ResponseYou've already chosen the best response.0
so you are saying that sin(infinity)= 0 ? would that mean, according to you, sin(infinity + pi/2) =1 ?
 one year ago

Goten77Best ResponseYou've already chosen the best response.0
no shub because like with any limits if i had like 1/(x+1) the limit as x> infiity is not really impacted by the +1 so in ur example the pi/2 doenst really effect infiity
 one year ago

agent0smithBest ResponseYou've already chosen the best response.1
Look at a graph of sinx, cosx, or tanx, as x gets larger... what happens to the graph?
 one year ago

Goten77Best ResponseYou've already chosen the best response.0
man i wish shub was here so he could put in on this...
 one year ago

agent0smithBest ResponseYou've already chosen the best response.1
Or look at this animation of simple harmonic motion (makes a sinusoidal wave): http://upload.wikimedia.org/wikipedia/commons/7/74/Simple_harmonic_motion_animation.gif No matter how long you watch that, is the amplitude ever going to change?
 one year ago

KainuiBest ResponseYou've already chosen the best response.1
There is no limit as x goes to infinity of sinx or cosx, this is a fact. They are constantly oscillating between 1 and 1, so you can't say for certain that it becomes anything at infinity.
 one year ago

Goten77Best ResponseYou've already chosen the best response.0
its something like .. the limit doesnt exist... but it is assumed it would = 0 for sinx and assumed 1 on cosx
 one year ago

KainuiBest ResponseYou've already chosen the best response.1
No it isn't, never, you're flat out wrong.
 one year ago

Goten77Best ResponseYou've already chosen the best response.0
its what my high school teacher and college professor said...
 one year ago

KainuiBest ResponseYou've already chosen the best response.1
Your high school teacher and college professors are wrong or you misheard them.
 one year ago

Goten77Best ResponseYou've already chosen the best response.0
well if u had to guess a number... what would u guess?
 one year ago

Goten77Best ResponseYou've already chosen the best response.0
it was something like probability led the solution to kinda* exist
 one year ago

KainuiBest ResponseYou've already chosen the best response.1
There's no guessing involved, as you increase to infinity sine and cosine functions do not converge towards anything. They will keep going between 1 and +1 forever.
 one year ago

Goten77Best ResponseYou've already chosen the best response.0
thats true... but 0 occurs .... tbh i cant explain it like they did
 one year ago

KainuiBest ResponseYou've already chosen the best response.1
The only time you might have a limit with sine or cosine converging towards something might be something like: \[\lim_{x \rightarrow \infty }\frac{ sinx }{ x }=0\]
 one year ago

agent0smithBest ResponseYou've already chosen the best response.1
^ it's probably something like what kainui posted. Damped oscillation.
 one year ago

Goten77Best ResponseYou've already chosen the best response.0
XD this question always gets every1 involved
 one year ago
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