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\[L^{1} (\frac{2s^3}{s^281})\]
The actual problem in the problem set is
\[L^{1} (\frac{2s^3}{s^481})\]
 one year ago
 one year ago
\[L^{1} (\frac{2s^3}{s^281})\] The actual problem in the problem set is \[L^{1} (\frac{2s^3}{s^481})\]
 one year ago
 one year ago

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RolyPolyBest ResponseYou've already chosen the best response.0
\[L^{1} (\frac{2s^3}{s^281})=L^{1} (2s+\frac{81}{s9}+\frac{81}{s+9})\]
 one year ago

RolyPolyBest ResponseYou've already chosen the best response.0
I don't like Laplace /_\
 one year ago

hartnnBest ResponseYou've already chosen the best response.1
i assume, thats correct, so whats the problem ?
 one year ago

RolyPolyBest ResponseYou've already chosen the best response.0
\[L^{1}(2s)=trouble\] Btw.. I... suddenly... discovered that... I read the problem wrong :\
 one year ago

RolyPolyBest ResponseYou've already chosen the best response.0
But how to find \(L^{1}(2s)\)?
 one year ago

RolyPolyBest ResponseYou've already chosen the best response.0
For the correct question in the problem set: \[L^{1} (\frac{2s^3}{s^481})\]\[=L^{1} (\frac{2s^3}{s^481})\]\[=L^{1} (\frac{s}{s^2+9}+\frac{1}{2(s3)}+\frac{1}{2(s+3)})\]\[=cos(3t)+cosh(3t)\]
 one year ago

hartnnBest ResponseYou've already chosen the best response.1
sorry, my computer restarted.... to get L^{1} (2s), u just replace 's' by 2s ....
 one year ago

RolyPolyBest ResponseYou've already chosen the best response.0
L^{1} (s) also looks weird to me... Usually, it's a/s^n which I can do the inverse easily (easier, I mean)..
 one year ago

hartnnBest ResponseYou've already chosen the best response.1
ohh...i read that wrong .. u know whats L^{1} s ?
 one year ago

hartnnBest ResponseYou've already chosen the best response.1
its \(\delta'(t)\) so, \(L^{1}(2s) = 2\delta'(t)\)
 one year ago

RolyPolyBest ResponseYou've already chosen the best response.0
What is \(\delta'(t)\)?
 one year ago

hartnnBest ResponseYou've already chosen the best response.1
u know what is \(\delta(t) ?\)
 one year ago

hartnnBest ResponseYou've already chosen the best response.1
Dirac delta function.. and ' means its derivative
 one year ago

RolyPolyBest ResponseYou've already chosen the best response.0
I.. don't remember I've learnt such function...
 one year ago

hartnnBest ResponseYou've already chosen the best response.1
really ? http://en.wikipedia.org/wiki/Dirac_delta_function 0 everywhere except origin.....like an impulse.
 one year ago

RolyPolyBest ResponseYou've already chosen the best response.0
I think I've only learnt int. from 0 to infty and from s to infty case, not the ve infty to +ve infty... Thanks for introducing a new friend to me though :)
 one year ago

RolyPolyBest ResponseYou've already chosen the best response.0
I want to get back my words. I don't know the name of this new friend, but he's just an old friend of mine :'( I'm sorry!!
 one year ago
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