## swiftskier96 Group Title Help!?!?!?!? For questions 1 and 2, write the expression as a single logarithm. (Problem written below) logb (q^2 + t^8) logb(q^2t^8) logb(qt^(2+8)) In this answer, the 2+8 is the entire exponent. (2 + 8) logb (q + t) one year ago one year ago

1. swiftskier96 Group Title

$2\log_{b}q + 8\log_{b}t$

2. swiftskier96 Group Title

logb (q^2 + t^8) logb(q^2t^8) logb(qt^(2+8)) In this answer, the 2+8 is the entire exponent. (2 + 8) logb (q + t)

3. swiftskier96 Group Title

2. 4 log x – 6 log (x + 2) (1 point) 24 log x/x + 2 log x^4(x + 2)^6 log x (x + 2)^24 none of these

4. phi Group Title

I don't see what you can do with the first one. for the 2nd one, can't you bring the 4 inside the log using $\log(x^b)= b\log(x)$ in the opposite order same for the 6 then you can replace the subtraction of logs with division inside the log

5. phi Group Title

oh, I see what the first question is: make $2\log_{b}q + 8\log_{b}t$ into one log it is the same problem as the other one. bring the 2 inside. bring the 8 inside then change + logs to multiplication inside the log

6. swiftskier96 Group Title

Is #2 B?

7. phi Group Title

B is close, but the -6 is ruining it. you change (you really should try doing this) the expression from 4 log x – 6 log (x + 2) to log x^4 - log( (x+2)^6 ) if we were adding then B would be the answer. but the - means you divide log ( x^4/ (x+2)^6 ) or using negative exponents $\log(x^4 (x+2)^{-6})$ so unless there is a typo, B is not it.

8. androidonyourface Group Title

c?

9. swiftskier96 Group Title

So if you divide the log, it would be A? (Sorry if its wrong. Im really trying my best to understand.)

10. androidonyourface Group Title

@phi

11. phi Group Title

I don't think the answer is among your choices move the 4 and the 6 inside the log $4 \log x – 6 \log (x + 2)$ becomes $\log( x^4) - \log( (x+2)^6 )$ the - means you divide $\log \left( \frac{x^4}{ (x+2)^6} \right)$

12. swiftskier96 Group Title

Oh ok. So it would have to be D.

13. phi Group Title

yes. can you take a shot at the first problem?

14. swiftskier96 Group Title

I can try. Hold on.

15. swiftskier96 Group Title

Would #1 be B?

16. phi Group Title

$2\log_{b}q + 8\log_{b}t$ bring the 2 and and 8 inside (all base b, but I'm not typing it in) $\log(q^2) + \log(t^8)$ adding logs changes to multiplication inside a log (in the old days people did this the other way round, because adding is easier then multiplying long numbers) $\log(q^2t^8)$

17. swiftskier96 Group Title

Hey, i got it right! Lol Thanks!!! :)

18. phi Group Title

yw