A community for students. Sign up today!
Here's the question you clicked on:
 0 viewing
 2 years ago
A SMALL BOB IS IN CONTACT WITH THE WEDGE AND THE ROD HOLDING THE BOG IS LIGHT AND VERTICALLY INITIALLY. NOW THE BOB IS DISPLACED AND THE SYSTEM STARTS MOVING. THE BOB AND WEDGE LOOSE CONTACT WHEN ANGLE BETWEEN HORIZONTAL AND ROD IS 30. FIND THE ACCELERATION OF THE WEDGE AT THIS INSTANT
 2 years ago
A SMALL BOB IS IN CONTACT WITH THE WEDGE AND THE ROD HOLDING THE BOG IS LIGHT AND VERTICALLY INITIALLY. NOW THE BOB IS DISPLACED AND THE SYSTEM STARTS MOVING. THE BOB AND WEDGE LOOSE CONTACT WHEN ANGLE BETWEEN HORIZONTAL AND ROD IS 30. FIND THE ACCELERATION OF THE WEDGE AT THIS INSTANT

This Question is Closed

exploringphysics
 2 years ago
Best ResponseYou've already chosen the best response.0ALSO FRICTIN IS ABSENT SEE THIS IMAGE dw:1355853151871:dw

Robinronaldo
 one year ago
Best ResponseYou've already chosen the best response.1I don't see the wedge in the image. I just see bob, rod and a wooden square block

exploringphysics
 one year ago
Best ResponseYou've already chosen the best response.0the square box ,[you say] is a wedge only. just solve this .....

Robinronaldo
 one year ago
Best ResponseYou've already chosen the best response.1can you share your progress on the question?

exploringphysics
 one year ago
Best ResponseYou've already chosen the best response.0I wrote equations for motion using newton laws and tried to put N(between) wedge and bob to be zero . this gives me the tangential acc. of bob as gcos@ [@ is angle btw horizontal and rod. here it's 30]. But what is acc. for the wedge??????dw:1356000602528:dw

Robinronaldo
 one year ago
Best ResponseYou've already chosen the best response.1give me some time, I am on it...

Robinronaldo
 one year ago
Best ResponseYou've already chosen the best response.1Here you go! Let me know what you think?

exploringphysics
 one year ago
Best ResponseYou've already chosen the best response.0NO the radial acc. can't be zero . the particle still rotates and need mw^2r towards the hinge......... :( try anything else

Saikam
 one year ago
Best ResponseYou've already chosen the best response.0acceleration of the wedge is ZEROOOOOOOWWWW . speed is not. because at the instant the bob loses contact with the wedge, who else would apply a force on it? no body! so acceleration =0

shubhamsrg
 one year ago
Best ResponseYou've already chosen the best response.0@Saikam accn =0 after that instant is history. But we are asked about accn at that very instant.

Saikam
 one year ago
Best ResponseYou've already chosen the best response.0wat is the force required to lift a 4kg block off the floor ? take g = 10 m/s2

Saikam
 one year ago
Best ResponseYou've already chosen the best response.0we generally say it is 40N . but if u apply 4N, the net force would still be zzero and the block should not move. actually we need a force just greater than 40N . But we usually call it 40N. This is the same case. the acceleration would be just greater than 0. but we can say it is =0

VincentLyon.Fr
 one year ago
Best ResponseYou've already chosen the best response.0Saikam is right: at instant of separation, contact force becomes zero, so acceleration of wedge is 0 too.
Ask your own question
Ask a QuestionFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.