Here's the question you clicked on:
lawls
sketch the graph of the polar equation. r = theta
it has not any special method , just first give theta some value , then do this for r
oh let me explain more first suppose r=1,then for theta between 0 to 2pi what shape do you have? surely a circle with radius r , now change r you will have lots of circles
so it basically looks like a spiral?
|dw:1355872768424:dw| I think it'll look like this.... my sketch is ugly, i know
Well shining isn't quite right. Because if you pick an r you're also picking a theta as they are equal... So as r grows so does theta linearly. So in polar it should look something like this: |dw:1355872808171:dw|