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shining
 2 years ago
Best ResponseYou've already chosen the best response.0it has not any special method , just first give theta some value , then do this for r

shining
 2 years ago
Best ResponseYou've already chosen the best response.0oh let me explain more first suppose r=1,then for theta between 0 to 2pi what shape do you have? surely a circle with radius r , now change r you will have lots of circles

lawls
 2 years ago
Best ResponseYou've already chosen the best response.0so it basically looks like a spiral?

estebananaya
 2 years ago
Best ResponseYou've already chosen the best response.0dw:1355872768424:dw I think it'll look like this.... my sketch is ugly, i know

malevolence19
 2 years ago
Best ResponseYou've already chosen the best response.0Well shining isn't quite right. Because if you pick an r you're also picking a theta as they are equal... So as r grows so does theta linearly. So in polar it should look something like this: dw:1355872808171:dw
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