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shiningBest ResponseYou've already chosen the best response.0
it has not any special method , just first give theta some value , then do this for r
 one year ago

shiningBest ResponseYou've already chosen the best response.0
oh let me explain more first suppose r=1,then for theta between 0 to 2pi what shape do you have? surely a circle with radius r , now change r you will have lots of circles
 one year ago

lawlsBest ResponseYou've already chosen the best response.0
so it basically looks like a spiral?
 one year ago

estebananayaBest ResponseYou've already chosen the best response.0
dw:1355872768424:dw I think it'll look like this.... my sketch is ugly, i know
 one year ago

malevolence19Best ResponseYou've already chosen the best response.0
Well shining isn't quite right. Because if you pick an r you're also picking a theta as they are equal... So as r grows so does theta linearly. So in polar it should look something like this: dw:1355872808171:dw
 one year ago

malevolence19Best ResponseYou've already chosen the best response.0
http://www.wolframalpha.com/input/?i=polar+plot+r+%3D+theta
 one year ago
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