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\[4*\log_{x}2=\log_{2}x+3 \]
(4*logx 2 = log2 x + 3)

what is your question, exactly?

Find x ? :D

i think you can start by putting logx 2=log2 2/ log2 x

i didn't get the answer, but i think the procedure is correct

first write log 2 x into 1/(logx 2)
then t=logx 2
solve it!

hint:you will get two values that just one of them is acceptable

I got for x 2 and 1/16, why is only one acceptable?

i think both are acceptable