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wladston

  • 3 years ago

I need to calculate Integral (F . dr), where F(x,y,z) = (z^2, xz, 2xy) and C is the curve obtained from the intersection of the surface z=1-y^2, when z>=0 and the plane 2x+3z=6. I'm trying that one for over 5 hours already...

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  1. richyw
    • 3 years ago
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    hmm. what have you done so far?

  2. wladston
    • 3 years ago
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    so far I've made a sketch of the surface, I calculated curl F and I applied the stoke's theorem to get Integral ( <x, 2y-2z,z>) dS. I have no idea how to move on.

  3. richyw
    • 3 years ago
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    wait why is that integral a vector? sorry I am just learning this stuff right now. I'm not even in vector calculus yet. just the basics from multivariable calc. I would like to see how to do this as well!

  4. wladston
    • 3 years ago
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    Over 8 hours trying to solve this problem, still nothing :( Well, it's a vector integral because the integral is not over a scalar function, but over a vector field ... this stuff is complex. I'll have an exam tomorrow morning (my final) and I can see I'm completely screwed ...

  5. wladston
    • 3 years ago
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    it looks like I can transform this integral I'm left with using this relation : (attached image) I just don't know how to apply this into my integral :(

  6. wladston
    • 3 years ago
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    mainly because I don't know how to calculate the normal of a surface.

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