A community for students. Sign up today!
Here's the question you clicked on:
 0 viewing
 2 years ago
HEEEEELLLLPPPP MEEEEEEE!!!!!Solve the systems using substitution.
6x + 2y = 0
4x + y = 1
3x + 2y = 4
x + 2y = 8
5x  4y = 14
x  2y = 2
x + 3y = 4
4x + 5y = 5
x + 3y = 5
2x  y = 18
 2 years ago
HEEEEELLLLPPPP MEEEEEEE!!!!!Solve the systems using substitution. 6x + 2y = 0 4x + y = 1 3x + 2y = 4 x + 2y = 8 5x  4y = 14 x  2y = 2 x + 3y = 4 4x + 5y = 5 x + 3y = 5 2x  y = 18

This Question is Closed

nickersia
 2 years ago
Best ResponseYou've already chosen the best response.0You need to multiply one of the equation, to make them that way so you can ignore x or y For example: 6x + 2y = 0 4x + y = 1 If you multiply first one you want to get 4x (which is hard option) or y (again hard option) If you multiply second one you want to get 6x (again hard) or 2y (easiest one) So you multiply second equation by 2 and you will get 8x2y=2 Now you can ignore +2y and 2y And you just sum the rest 6x+(8x)=0+2 You can find x easily, and then go back to any of them use the x you find, and find y... Simple enough? You get the idea? Practice :) Good luck! :)
Ask your own question
Ask a QuestionFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.