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HEEEEELLLLPPPP MEEEEEEE!!!!!Solve the systems using substitution.
6x + 2y = 0
4x + y = 1
3x + 2y = 4
x + 2y = 8
5x  4y = 14
x  2y = 2
x + 3y = 4
4x + 5y = 5
x + 3y = 5
2x  y = 18
 one year ago
 one year ago
HEEEEELLLLPPPP MEEEEEEE!!!!!Solve the systems using substitution. 6x + 2y = 0 4x + y = 1 3x + 2y = 4 x + 2y = 8 5x  4y = 14 x  2y = 2 x + 3y = 4 4x + 5y = 5 x + 3y = 5 2x  y = 18
 one year ago
 one year ago

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nickersiaBest ResponseYou've already chosen the best response.0
You need to multiply one of the equation, to make them that way so you can ignore x or y For example: 6x + 2y = 0 4x + y = 1 If you multiply first one you want to get 4x (which is hard option) or y (again hard option) If you multiply second one you want to get 6x (again hard) or 2y (easiest one) So you multiply second equation by 2 and you will get 8x2y=2 Now you can ignore +2y and 2y And you just sum the rest 6x+(8x)=0+2 You can find x easily, and then go back to any of them use the x you find, and find y... Simple enough? You get the idea? Practice :) Good luck! :)
 one year ago

johanaBest ResponseYou've already chosen the best response.0
thank u :)) @ nickersia
 one year ago
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