A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 3 years ago
By using substitution:
15x+3y=5
5x+y=6
Show me how to do this.
anonymous
 3 years ago
By using substitution: 15x+3y=5 5x+y=6 Show me how to do this.

This Question is Closed

zepdrix
 3 years ago
Best ResponseYou've already chosen the best response.2Let's manipulate the second equation, we'll get it in terms of y=, and then we'll PLUG it into the first equation. \[\large 5x+y=6\]Subtracting 5x from both sides gives us,\[\large y=\color{cadetblue}{65x}\]We want to plug this in for the y in the other equation.\[\large 15x+3\color{cadetblue}{y}=5\] Which gives us,\[\huge 15x+3\color{cadetblue}{(65x)}=5\]

zepdrix
 3 years ago
Best ResponseYou've already chosen the best response.2We SUBSTITUTED one equation into the other one. From here it's not too bad. We just have to multiply the 3 by each term in the brackets, and then solve for x. If you're still confused, let me know.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0See this http://openstudy.com/study#/updates/50d0ff5ce4b0091849d7a6f6

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0@nickersia Oh thanks.
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.