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brendakayyyBest ResponseYou've already chosen the best response.0
a computer company determines its profit equation in millions of dollars given by p=x^348x^2+720x1000 where x is the number of thousands of units of software sold
 one year ago

brendakayyyBest ResponseYou've already chosen the best response.0
and 0<x<40 optimize the manufactures profit
 one year ago

Goten77Best ResponseYou've already chosen the best response.1
im thinking this is really ez.... but maybe im wrong.... since from 040 it looks like a line almost.... wouldnt (40,y) b the maximum?
 one year ago

zepdrixBest ResponseYou've already chosen the best response.1
dw:1355889094401:dwIt's a cubic function, so it's going to have this shape. As I've illustrated in the picture, it is possible that 40 might not be the maximum profit value. So we'll have to do some work to find out where that point is.
 one year ago

brendakayyyBest ResponseYou've already chosen the best response.0
do i differentiate the function and find the critical values?
 one year ago

zepdrixBest ResponseYou've already chosen the best response.1
\[\large P(x)=x^348x^2+720x1000\]Yes very good. You'll want to find Critical Points, and since this is a CLOSED INTERVAL, also check the END POINTS! Then simply plug each value into the function, and see which gives you the largest output.
 one year ago

Goten77Best ResponseYou've already chosen the best response.1
oh if thats how it looked then i graphed it wrong.. my bad
 one year ago

zepdrixBest ResponseYou've already chosen the best response.1
Hmm I better throw it into wolfram and make sure I'm not way off.. cause I was just doing that based off of memory :P
 one year ago

Goten77Best ResponseYou've already chosen the best response.1
but anyways it be best to just find derivative.. and critical points.. then find values of those and the 0/40 and then u get ur answer
 one year ago

brendakayyyBest ResponseYou've already chosen the best response.0
would my critical values be x<12, 12<x<20, X>20?
 one year ago

Goten77Best ResponseYou've already chosen the best response.1
ur critical valued would be points.....
 one year ago

zepdrixBest ResponseYou've already chosen the best response.1
You got the correct points, x=12, x=20. I'm not sure why you wrote them as intervals though :)
 one year ago

zepdrixBest ResponseYou've already chosen the best response.1
Now you want to plug your values into P(x) and compare, to find out which one gives you the largest value within this closed interval.\[\large P(12),\quad P(20), \quad P(0), \quad P(40)\]
 one year ago

brendakayyyBest ResponseYou've already chosen the best response.0
well cuz you base your values off the intervals according to my teacher
 one year ago

brendakayyyBest ResponseYou've already chosen the best response.0
what equation would i plug that into?
 one year ago

zepdrixBest ResponseYou've already chosen the best response.1
The original equation.
 one year ago

brendakayyyBest ResponseYou've already chosen the best response.0
whered you get the P(40) and P(0)
 one year ago

Goten77Best ResponseYou've already chosen the best response.1
there apart of the domain.. so there possible maxs's mins
 one year ago

brendakayyyBest ResponseYou've already chosen the best response.0
oh thats what was meant by end points so if it were aclosed interval i would not take the end points into consideration right?
 one year ago

brendakayyyBest ResponseYou've already chosen the best response.0
what are the dimensions of the square based open top box that has a volume of 20 cubic inches and smallest surface area?
 one year ago

brendakayyyBest ResponseYou've already chosen the best response.0
can someone help me with this one ^
 one year ago

ZarkonBest ResponseYou've already chosen the best response.0
if you have a new question you should put it in a new thread
 one year ago
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