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brendakayyy
 2 years ago
Best ResponseYou've already chosen the best response.0a computer company determines its profit equation in millions of dollars given by p=x^348x^2+720x1000 where x is the number of thousands of units of software sold

brendakayyy
 2 years ago
Best ResponseYou've already chosen the best response.0and 0<x<40 optimize the manufactures profit

Goten77
 2 years ago
Best ResponseYou've already chosen the best response.1im thinking this is really ez.... but maybe im wrong.... since from 040 it looks like a line almost.... wouldnt (40,y) b the maximum?

zepdrix
 2 years ago
Best ResponseYou've already chosen the best response.1dw:1355889094401:dwIt's a cubic function, so it's going to have this shape. As I've illustrated in the picture, it is possible that 40 might not be the maximum profit value. So we'll have to do some work to find out where that point is.

brendakayyy
 2 years ago
Best ResponseYou've already chosen the best response.0do i differentiate the function and find the critical values?

zepdrix
 2 years ago
Best ResponseYou've already chosen the best response.1\[\large P(x)=x^348x^2+720x1000\]Yes very good. You'll want to find Critical Points, and since this is a CLOSED INTERVAL, also check the END POINTS! Then simply plug each value into the function, and see which gives you the largest output.

Goten77
 2 years ago
Best ResponseYou've already chosen the best response.1oh if thats how it looked then i graphed it wrong.. my bad

zepdrix
 2 years ago
Best ResponseYou've already chosen the best response.1Hmm I better throw it into wolfram and make sure I'm not way off.. cause I was just doing that based off of memory :P

Goten77
 2 years ago
Best ResponseYou've already chosen the best response.1but anyways it be best to just find derivative.. and critical points.. then find values of those and the 0/40 and then u get ur answer

brendakayyy
 2 years ago
Best ResponseYou've already chosen the best response.0would my critical values be x<12, 12<x<20, X>20?

Goten77
 2 years ago
Best ResponseYou've already chosen the best response.1ur critical valued would be points.....

zepdrix
 2 years ago
Best ResponseYou've already chosen the best response.1You got the correct points, x=12, x=20. I'm not sure why you wrote them as intervals though :)

zepdrix
 2 years ago
Best ResponseYou've already chosen the best response.1Now you want to plug your values into P(x) and compare, to find out which one gives you the largest value within this closed interval.\[\large P(12),\quad P(20), \quad P(0), \quad P(40)\]

brendakayyy
 2 years ago
Best ResponseYou've already chosen the best response.0well cuz you base your values off the intervals according to my teacher

brendakayyy
 2 years ago
Best ResponseYou've already chosen the best response.0what equation would i plug that into?

brendakayyy
 2 years ago
Best ResponseYou've already chosen the best response.0whered you get the P(40) and P(0)

Goten77
 2 years ago
Best ResponseYou've already chosen the best response.1there apart of the domain.. so there possible maxs's mins

brendakayyy
 2 years ago
Best ResponseYou've already chosen the best response.0oh thats what was meant by end points so if it were aclosed interval i would not take the end points into consideration right?

brendakayyy
 2 years ago
Best ResponseYou've already chosen the best response.0what are the dimensions of the square based open top box that has a volume of 20 cubic inches and smallest surface area?

brendakayyy
 2 years ago
Best ResponseYou've already chosen the best response.0can someone help me with this one ^

Zarkon
 2 years ago
Best ResponseYou've already chosen the best response.0if you have a new question you should put it in a new thread
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