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ILKGA

  • 3 years ago

Find the molar mass of AgNO3 given the following atomic masses: AG = 107.9 u, N = 14.01 u, O = 16.00 u. Remember to round to proper significant figures

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  1. NotTim
    • 3 years ago
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    What formula(s) relate to this question?

  2. ILKGA
    • 3 years ago
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    \[AgNO _{3}\]

  3. NotTim
    • 3 years ago
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    No, 'mathematical' formulas.

  4. ILKGA
    • 3 years ago
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    nope all the info I was given is in the question above

  5. NotTim
    • 3 years ago
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    You don't have a formula sheet? Or liek a textbook with the formulas?

  6. ILKGA
    • 3 years ago
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    What it has is an example problem but I don't see any formula. Do you want the example problem?

  7. NotTim
    • 3 years ago
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    Something like that?

  8. ILKGA
    • 3 years ago
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    I don't have anything like that. O_o

  9. NotTim
    • 3 years ago
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    oh.

  10. NotTim
    • 3 years ago
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    Anyways, first add all the atomic masses together (do remember to multiply oxygen's atomic mass by 3 though, because there are 3 oxygen molecules in each AgNO3 molecule).

  11. NotTim
    • 3 years ago
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    Wait, is that all you do? I forgot.

  12. ILKGA
    • 3 years ago
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    so . 107.9 + 14.01 x 16.00(3) = 169.91

  13. NotTim
    • 3 years ago
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    you don't have to multiply the value of oxygen to the 'main body'. just multiply it by 3, then add it to the others.

  14. ILKGA
    • 3 years ago
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    that was supposed to be an addition sign sorry 107.9 + 14.01 + 48 = 169.91

  15. NotTim
    • 3 years ago
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    good enuff.

  16. NotTim
    • 3 years ago
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    We clear now? You know why the oxygen molecule was multiplied by 3?

  17. ILKGA
    • 3 years ago
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    yup

  18. NotTim
    • 3 years ago
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    awesome. SMOKEBOMB. POOf. NOTTIM AWAYYYY

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