jackyluvv 2 years ago What? Dont understand... Help anyone Solve: |5x + 2| + 7 < 19 A. x < 2 and x > -14/5 B. x < 2 and x < -14/5 C. x > 2 and x > 14/5 D. x > 2

1. Hero

|5x + 2| + 7 < 19 |5x + 2| < 19 - 7 |5x + 2| < 12 -12 < 5x + 2 < 12 -12 - 2 < 5x < 12 - 2 -14 < 5x < 10 Divide all sides by 5 to finish

2. jackyluvv

so b)?

3. oddfishout

first solve the problem assuming that the part in the absolute value brackets is positive. so 5x+2+7<19. to solve for x, subtract 7 and 2 from both sides. so 5x<10. then divide by 5. x<2. then assume that the part in absolute value brackets is negative and solve for x. -5x-2+7<19. -5x<14 whenever you divide by a negative, switch the inequality sign so x>-14/5

4. Hero

Not b bro. Make sure you are paying close attention to the signs. Don't confuse yourself @jackyluvv @oddfishout, no need to divide by a negative for this one.

5. oddfishout

why not.... -(5x+2)= -5x-2....right....

6. Hero

Bro |5x + 2| = 5x + 2 Don't use negatives when you don't need to

7. oddfishout

Dude. We got the same answers, just differently... no biggy. To each his own.

8. Hero

Yeah, but you did yours the hard way. I am not in agreement with your strategy.

9. oddfishout

so....that is totally okay with me. But it doesn't make me wrong.

10. Hero

All you need to remember is this rule for absolute value: |x + a| < c means the same as -c < x + a < c