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jackyluvv Group Title

What? Dont understand... Help anyone Solve: |5x + 2| + 7 < 19 A. x < 2 and x > -14/5 B. x < 2 and x < -14/5 C. x > 2 and x > 14/5 D. x > 2

  • one year ago
  • one year ago

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  1. Hero Group Title
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    |5x + 2| + 7 < 19 |5x + 2| < 19 - 7 |5x + 2| < 12 -12 < 5x + 2 < 12 -12 - 2 < 5x < 12 - 2 -14 < 5x < 10 Divide all sides by 5 to finish

    • one year ago
  2. jackyluvv Group Title
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    so b)?

    • one year ago
  3. oddfishout Group Title
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    first solve the problem assuming that the part in the absolute value brackets is positive. so 5x+2+7<19. to solve for x, subtract 7 and 2 from both sides. so 5x<10. then divide by 5. x<2. then assume that the part in absolute value brackets is negative and solve for x. -5x-2+7<19. -5x<14 whenever you divide by a negative, switch the inequality sign so x>-14/5

    • one year ago
  4. Hero Group Title
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    Not b bro. Make sure you are paying close attention to the signs. Don't confuse yourself @jackyluvv @oddfishout, no need to divide by a negative for this one.

    • one year ago
  5. oddfishout Group Title
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    why not.... -(5x+2)= -5x-2....right....

    • one year ago
  6. Hero Group Title
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    Bro |5x + 2| = 5x + 2 Don't use negatives when you don't need to

    • one year ago
  7. oddfishout Group Title
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    Dude. We got the same answers, just differently... no biggy. To each his own.

    • one year ago
  8. Hero Group Title
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    Yeah, but you did yours the hard way. I am not in agreement with your strategy.

    • one year ago
  9. oddfishout Group Title
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    so....that is totally okay with me. But it doesn't make me wrong.

    • one year ago
  10. Hero Group Title
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    All you need to remember is this rule for absolute value: |x + a| < c means the same as -c < x + a < c

    • one year ago
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