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anonymous
 4 years ago
What? Dont understand... Help anyone
Solve: 5x + 2 + 7 < 19
A. x < 2 and x > 14/5
B. x < 2 and x < 14/5
C. x > 2 and x > 14/5
D. x > 2
anonymous
 4 years ago
What? Dont understand... Help anyone Solve: 5x + 2 + 7 < 19 A. x < 2 and x > 14/5 B. x < 2 and x < 14/5 C. x > 2 and x > 14/5 D. x > 2

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Hero
 4 years ago
Best ResponseYou've already chosen the best response.25x + 2 + 7 < 19 5x + 2 < 19  7 5x + 2 < 12 12 < 5x + 2 < 12 12  2 < 5x < 12  2 14 < 5x < 10 Divide all sides by 5 to finish

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0first solve the problem assuming that the part in the absolute value brackets is positive. so 5x+2+7<19. to solve for x, subtract 7 and 2 from both sides. so 5x<10. then divide by 5. x<2. then assume that the part in absolute value brackets is negative and solve for x. 5x2+7<19. 5x<14 whenever you divide by a negative, switch the inequality sign so x>14/5

Hero
 4 years ago
Best ResponseYou've already chosen the best response.2Not b bro. Make sure you are paying close attention to the signs. Don't confuse yourself @jackyluvv @oddfishout, no need to divide by a negative for this one.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0why not.... (5x+2)= 5x2....right....

Hero
 4 years ago
Best ResponseYou've already chosen the best response.2Bro 5x + 2 = 5x + 2 Don't use negatives when you don't need to

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Dude. We got the same answers, just differently... no biggy. To each his own.

Hero
 4 years ago
Best ResponseYou've already chosen the best response.2Yeah, but you did yours the hard way. I am not in agreement with your strategy.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0so....that is totally okay with me. But it doesn't make me wrong.

Hero
 4 years ago
Best ResponseYou've already chosen the best response.2All you need to remember is this rule for absolute value: x + a < c means the same as c < x + a < c
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