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What? Dont understand... Help anyone
Solve: 5x + 2 + 7 < 19
A. x < 2 and x > 14/5
B. x < 2 and x < 14/5
C. x > 2 and x > 14/5
D. x > 2
 one year ago
 one year ago
What? Dont understand... Help anyone Solve: 5x + 2 + 7 < 19 A. x < 2 and x > 14/5 B. x < 2 and x < 14/5 C. x > 2 and x > 14/5 D. x > 2
 one year ago
 one year ago

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HeroBest ResponseYou've already chosen the best response.2
5x + 2 + 7 < 19 5x + 2 < 19  7 5x + 2 < 12 12 < 5x + 2 < 12 12  2 < 5x < 12  2 14 < 5x < 10 Divide all sides by 5 to finish
 one year ago

oddfishoutBest ResponseYou've already chosen the best response.0
first solve the problem assuming that the part in the absolute value brackets is positive. so 5x+2+7<19. to solve for x, subtract 7 and 2 from both sides. so 5x<10. then divide by 5. x<2. then assume that the part in absolute value brackets is negative and solve for x. 5x2+7<19. 5x<14 whenever you divide by a negative, switch the inequality sign so x>14/5
 one year ago

HeroBest ResponseYou've already chosen the best response.2
Not b bro. Make sure you are paying close attention to the signs. Don't confuse yourself @jackyluvv @oddfishout, no need to divide by a negative for this one.
 one year ago

oddfishoutBest ResponseYou've already chosen the best response.0
why not.... (5x+2)= 5x2....right....
 one year ago

HeroBest ResponseYou've already chosen the best response.2
Bro 5x + 2 = 5x + 2 Don't use negatives when you don't need to
 one year ago

oddfishoutBest ResponseYou've already chosen the best response.0
Dude. We got the same answers, just differently... no biggy. To each his own.
 one year ago

HeroBest ResponseYou've already chosen the best response.2
Yeah, but you did yours the hard way. I am not in agreement with your strategy.
 one year ago

oddfishoutBest ResponseYou've already chosen the best response.0
so....that is totally okay with me. But it doesn't make me wrong.
 one year ago

HeroBest ResponseYou've already chosen the best response.2
All you need to remember is this rule for absolute value: x + a < c means the same as c < x + a < c
 one year ago
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