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anonymous
 3 years ago
I need help/advice with an diracdelta integral. I computed the integral seen in the attachment and got 1. However, I am not quite sure if I did it right. Also, I don´t know how to throw this kind of integral with vectors in wolfram alpha.
anonymous
 3 years ago
I need help/advice with an diracdelta integral. I computed the integral seen in the attachment and got 1. However, I am not quite sure if I did it right. Also, I don´t know how to throw this kind of integral with vectors in wolfram alpha.

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0So, does this integral equal 1?

Kainui
 3 years ago
Best ResponseYou've already chosen the best response.0Isn't the area under the curve of the dirac delta function always equal to 1?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Yes, but it is a little bit different if you multiply it with another function, like here.

Kainui
 3 years ago
Best ResponseYou've already chosen the best response.0Well it's beyond my knowledge, that was literally all I knew about the dirac delta function lol.

experimentX
 3 years ago
Best ResponseYou've already chosen the best response.1is that triple integral??

Kainui
 3 years ago
Best ResponseYou've already chosen the best response.0I don't know if this helps or not. Seems like y^2... not sure... http://www.thefouriertransform.com/math/impulse.php

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0@experimentX No but it is a vector integral in R2.

experimentX
 3 years ago
Best ResponseYou've already chosen the best response.1what is your surface??

experimentX
 3 years ago
Best ResponseYou've already chosen the best response.1as for DeltaDirac, \[ \int_p^q \delta {(t  a)} f(t) dt = f(a) \; \text{ where a} \in (p, q)\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0@experimentX My integral looks a bit harder than your example. You can see it in the attachment.

experimentX
 3 years ago
Best ResponseYou've already chosen the best response.1I couldn't make head or tals out of it \[ \int_{\mathfrak{ R^3}} \delta(xy)x^2 dx \; \text{wobei} \; y = (0,1,2)^T \] Usually vector surface integrals are like \[\iint_s \vec F(x,y,z) \cdot d\vec s \] where 's' is some region of surface like plane or cylinder and F is vector valued function. ] http://tutorial.math.lamar.edu/Classes/CalcIII/SurfIntVectorField.aspx

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Got it. In this case the delta function must be y and therefore the integral is 0^2+1^2+2^2=5.

experimentX
 3 years ago
Best ResponseYou've already chosen the best response.1i see you have a point
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