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Solve 2 - 3 cos x = 5 + 3 cos x for 0 degrees lessthan x lessthan 180 degrees (1 point) can anyone help me...

Mathematics
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The possible answers are 150 degrees, 30 degrees, 60 degrees, and 120 degrees...?
Hey I'm tryin to figure this one out!!
Oh ok...if you could help me I would greatly appreciate it!!

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Other answers:

:) Sure thing. This is geomtry right? Or Algebra 2?
I think algebra 2...I'm in precal but shes going over several subject at one time...
Like an over view of algebra...
solve the equation. it will give you cosx=-1/2 --> x=120 degrees
thanks so much...could you help me answer another question @yrelhan4
cheers! only if i know it.
I have to find the angle the normal makes with the positive x-axis....& I have to rewrite it each equation in the normal for and solve the length of the normal... 1. 3x-2y-1=0 2. 5x+y-12=0 3. 4x+3y-4=0
If not its ok...but thanks anyway!!!
normal to these lines?
Yea..idk what it means either. :/ It said: find the angle the normal makes with the positive x–axis. Hint: You should first rewrite each equation in normal form and solve for the length of the normal.
see that normal from of a line is xsino + ysino =P whee o is angle made with positive x axis and p is the length of normal from origin to the line.
can you find a line perpendicular to the given lines and passing through origin?
Ok...no?
slope of a line is -(coefficient of x)/(coefficient of y). and m18m2 =-1 where m1 is the slope of the given line and m2 of the normal. write the normal line in the form of y=mx+c. substitute x,y=0,0 as it passes through the origin. this will give you value of c. plug this value back into the equation. suppose that the line is ax+by+c=0. thelength of perpendicular from x1,y1 is ax1 +by1+c/sqrt(a^2 + b^2). susbtitute 0,0 in place of x1,y1. this will give you value of perpendicular. i am still working on the angle. i seem to know it but cant recall it.
in the first line it is m2*m1=-1
If its confusing you & you can't figure it out its ok....I'm just not that good in math lol
just tell me if you get the length of the normal. or i'll you refer you to a site.
Can you just refer me....because I'm really confused
Sorry...
its alright sweety. i was as poorer at math. chill!! http://answers.yahoo.com/question/index?qid=20090817231959AASOXEf look at this to find the line perpendicular to the given line. and then look at my explanation. and i am not following the hint you gave me. i dont follow it. this method of mine makes more sense to me.
feel free to back to me if any problem.
slope of a line=tano. so arctan[-(coefficient of x)/coefficient of y)] will give you the angle.
ok thanks!!!

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