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sarahi_smiles
Group Title
Solve 2  3 cos x = 5 + 3 cos x for 0 degrees lessthan x lessthan 180 degrees (1 point)
can anyone help me...
 one year ago
 one year ago
sarahi_smiles Group Title
Solve 2  3 cos x = 5 + 3 cos x for 0 degrees lessthan x lessthan 180 degrees (1 point) can anyone help me...
 one year ago
 one year ago

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sarahi_smiles Group TitleBest ResponseYou've already chosen the best response.0
The possible answers are 150 degrees, 30 degrees, 60 degrees, and 120 degrees...?
 one year ago

BrittanyFrench Group TitleBest ResponseYou've already chosen the best response.0
Hey I'm tryin to figure this one out!!
 one year ago

sarahi_smiles Group TitleBest ResponseYou've already chosen the best response.0
Oh ok...if you could help me I would greatly appreciate it!!
 one year ago

BrittanyFrench Group TitleBest ResponseYou've already chosen the best response.0
:) Sure thing. This is geomtry right? Or Algebra 2?
 one year ago

sarahi_smiles Group TitleBest ResponseYou've already chosen the best response.0
I think algebra 2...I'm in precal but shes going over several subject at one time...
 one year ago

sarahi_smiles Group TitleBest ResponseYou've already chosen the best response.0
Like an over view of algebra...
 one year ago

yrelhan4 Group TitleBest ResponseYou've already chosen the best response.1
solve the equation. it will give you cosx=1/2 > x=120 degrees
 one year ago

sarahi_smiles Group TitleBest ResponseYou've already chosen the best response.0
thanks so much...could you help me answer another question @yrelhan4
 one year ago

yrelhan4 Group TitleBest ResponseYou've already chosen the best response.1
cheers! only if i know it.
 one year ago

sarahi_smiles Group TitleBest ResponseYou've already chosen the best response.0
I have to find the angle the normal makes with the positive xaxis....& I have to rewrite it each equation in the normal for and solve the length of the normal... 1. 3x2y1=0 2. 5x+y12=0 3. 4x+3y4=0
 one year ago

sarahi_smiles Group TitleBest ResponseYou've already chosen the best response.0
If not its ok...but thanks anyway!!!
 one year ago

yrelhan4 Group TitleBest ResponseYou've already chosen the best response.1
normal to these lines?
 one year ago

sarahi_smiles Group TitleBest ResponseYou've already chosen the best response.0
Yea..idk what it means either. :/ It said: find the angle the normal makes with the positive x–axis. Hint: You should first rewrite each equation in normal form and solve for the length of the normal.
 one year ago

yrelhan4 Group TitleBest ResponseYou've already chosen the best response.1
see that normal from of a line is xsino + ysino =P whee o is angle made with positive x axis and p is the length of normal from origin to the line.
 one year ago

yrelhan4 Group TitleBest ResponseYou've already chosen the best response.1
can you find a line perpendicular to the given lines and passing through origin?
 one year ago

sarahi_smiles Group TitleBest ResponseYou've already chosen the best response.0
Ok...no?
 one year ago

yrelhan4 Group TitleBest ResponseYou've already chosen the best response.1
slope of a line is (coefficient of x)/(coefficient of y). and m18m2 =1 where m1 is the slope of the given line and m2 of the normal. write the normal line in the form of y=mx+c. substitute x,y=0,0 as it passes through the origin. this will give you value of c. plug this value back into the equation. suppose that the line is ax+by+c=0. thelength of perpendicular from x1,y1 is ax1 +by1+c/sqrt(a^2 + b^2). susbtitute 0,0 in place of x1,y1. this will give you value of perpendicular. i am still working on the angle. i seem to know it but cant recall it.
 one year ago

yrelhan4 Group TitleBest ResponseYou've already chosen the best response.1
in the first line it is m2*m1=1
 one year ago

sarahi_smiles Group TitleBest ResponseYou've already chosen the best response.0
If its confusing you & you can't figure it out its ok....I'm just not that good in math lol
 one year ago

yrelhan4 Group TitleBest ResponseYou've already chosen the best response.1
just tell me if you get the length of the normal. or i'll you refer you to a site.
 one year ago

sarahi_smiles Group TitleBest ResponseYou've already chosen the best response.0
Can you just refer me....because I'm really confused
 one year ago

sarahi_smiles Group TitleBest ResponseYou've already chosen the best response.0
Sorry...
 one year ago

yrelhan4 Group TitleBest ResponseYou've already chosen the best response.1
its alright sweety. i was as poorer at math. chill!! http://answers.yahoo.com/question/index?qid=20090817231959AASOXEf look at this to find the line perpendicular to the given line. and then look at my explanation. and i am not following the hint you gave me. i dont follow it. this method of mine makes more sense to me.
 one year ago

yrelhan4 Group TitleBest ResponseYou've already chosen the best response.1
feel free to back to me if any problem.
 one year ago

yrelhan4 Group TitleBest ResponseYou've already chosen the best response.1
slope of a line=tano. so arctan[(coefficient of x)/coefficient of y)] will give you the angle.
 one year ago

sarahi_smiles Group TitleBest ResponseYou've already chosen the best response.0
ok thanks!!!
 one year ago
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