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this sounds like you need a computer program. what language?

No. I am learning this under maths, numerical analysis.

I am k with the first part of the question bt am stuck in the comparision part.

ya. bt hw abt the comparision part.

\(y=e^{\frac{x}{2}}-x\)
plug in x=0.3 and evaluate. compare to your answer using runge-kutta

bt y specifically 0.3

x= 0.3 y will be 0.862

ha k

The matlab gives
y= 0.861834234021667
the exact answer e^(0.15)-0.3 = 0.861834242728283

any luck?

trying