Quantcast

Got Homework?

Connect with other students for help. It's a free community.

  • across
    MIT Grad Student
    Online now
  • laura*
    Helped 1,000 students
    Online now
  • Hero
    College Math Guru
    Online now

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

Bladerunner1122 Group Title

A particle moves along the x-axis with the velocity given by v(t)=3t/(1+t^2) for t >or equal to 0. When t=0, the particle is at the point (4,0). 1. Determine the maximum velocity for the particle. Justify your answer. 2. Determine the position of the particle at any time t. 3. Find the limit of the velocity as t->infinity. 4. Find the limit of the position as t->infinity.

  • one year ago
  • one year ago

  • This Question is Closed
  1. shubhamsrg Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    dx = vdt use this..this little thing is supposed to do wonders for you ! :D

    • one year ago
  2. Bladerunner1122 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    Could you explain how that formula works please?

    • one year ago
  3. shubhamsrg Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    have you studied integration ?

    • one year ago
  4. Bladerunner1122 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    Just started learning it. It's not my best subject. xD

    • one year ago
  5. him1618 Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    the definition of velocity is v=dx/dt

    • one year ago
  6. Bladerunner1122 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    1. a(t) = 3(1-t^2)/(1+t^2)^2 max v at a=0, or t=1 v(1) = 3/2 2. x(t) = 3/2 log(1+t^2)+C at t=0, x=4, so 4 = 3/2 log(1+0) + C C = 4 x(t) = 3/2 log(1+t^2) + 4 3. v(t) → 0 as t→∞ 4. x(t) → ∞ that's what I've got so far. Does that make sense?

    • one year ago
  7. Bladerunner1122 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    @sauravshakya

    • one year ago
  8. shubhamsrg Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    you sure differentiated right in the 1st part.. rest all seem perfect! :)

    • one year ago
  9. Bladerunner1122 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    At least someone agrees with it so far.

    • one year ago
  10. shubhamsrg Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    i missed a question mark there :P i meant you sure differentiated right in the 1st part ???? :D cause i see that wrong..please confirm..

    • one year ago
  11. shubhamsrg Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    ohh wait//thats -t^2 // sorry sorry..thats correct..

    • one year ago
  12. shubhamsrg Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    my apologies! :P

    • one year ago
  13. Bladerunner1122 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    Yeah I just checked. oh well haha

    • one year ago
  14. Bladerunner1122 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    Could somebody please check this to make sure it makes sense? 1. dv/dt = [(1+t^2)(3) - 3t(2t)] / (t^2+1)^2 =[3 t^2 + 3 - 6 t^2 ] /(t^2+1)^2 zero when t= 1 (since t always >/=0) so the max v is at t = 1 then at t = 1 v(1) = 3/2 2. x(t) = 3/2 log(1+t^2)+C at t=0, x=4, so 4 = 3/2 log(1+0) + C C = 4 x(t) = 3/2 log(1+t^2) + 4 3. as t --> oo, v--> 3t/t^2 = 3/t = 0 4. as t -->oo, x --> (3/2)t^2 = oo

    • one year ago
    • Attachments:

See more questions >>>

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.