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Write the equation of a line parallel to the line 2x + 3y = 5 and passes through the point (9, 3). Please help I dont even know where to start.
 one year ago
 one year ago
Write the equation of a line parallel to the line 2x + 3y = 5 and passes through the point (9, 3). Please help I dont even know where to start.
 one year ago
 one year ago

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Dido525Best ResponseYou've already chosen the best response.1
Parallel lines have the same slope as the other line.
 one year ago

Dido525Best ResponseYou've already chosen the best response.1
Change your line to slope yintercept format.
 one year ago

Shikar23234Best ResponseYou've already chosen the best response.0
But the line has to pass through the point 9,3 at the same time. Thats whats confusing me.
 one year ago

Dido525Best ResponseYou've already chosen the best response.1
What is the slope of your line though? Do you recognize that?
 one year ago

Dido525Best ResponseYou've already chosen the best response.1
Change your line to y=mx+b format.
 one year ago

ryan123345Best ResponseYou've already chosen the best response.0
so then it is 3y = 2x + 5
 one year ago

Shikar23234Best ResponseYou've already chosen the best response.0
It would be 3y=2x+5
 one year ago

Dido525Best ResponseYou've already chosen the best response.1
@ryan123345 : let him do the work please.
 one year ago

Shikar23234Best ResponseYou've already chosen the best response.0
Oh. He already posted.
 one year ago

Dido525Best ResponseYou've already chosen the best response.1
Because we want the format: y=mx+b
 one year ago

Dido525Best ResponseYou've already chosen the best response.1
Okay but 5/3 is not 3.
 one year ago

Shikar23234Best ResponseYou've already chosen the best response.0
So just replace the 3 with 5/3
 one year ago

Dido525Best ResponseYou've already chosen the best response.1
Now do you see what the slope is?
 one year ago

Shikar23234Best ResponseYou've already chosen the best response.0
Ok now i got it. Thank you!
 one year ago

Dido525Best ResponseYou've already chosen the best response.1
Okay then. You are welcome :) .
 one year ago
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