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anonymous
 4 years ago
Write the equation of a line parallel to the line 2x + 3y = 5 and passes through the point (9, 3). Please help I dont even know where to start.
anonymous
 4 years ago
Write the equation of a line parallel to the line 2x + 3y = 5 and passes through the point (9, 3). Please help I dont even know where to start.

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Parallel lines have the same slope as the other line.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Change your line to slope yintercept format.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0But the line has to pass through the point 9,3 at the same time. Thats whats confusing me.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0What is the slope of your line though? Do you recognize that?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Change your line to y=mx+b format.

ryan123345
 4 years ago
Best ResponseYou've already chosen the best response.0so then it is 3y = 2x + 5

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0@ryan123345 : let him do the work please.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Oh. He already posted.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Okay now divide by 3.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Because we want the format: y=mx+b

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Okay but 5/3 is not 3.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0So just replace the 3 with 5/3

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Now do you see what the slope is?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Ok now i got it. Thank you!

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Okay then. You are welcome :) .
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