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Solve for x: \frac{ 1 }{ 27 }=9^{7x+3}

Mathematics
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I will adjust the format.. one moment..
make the bases of 2 sides equal to each other then u can equate the powers and find the value of x.
\[1/27=9^7x+3\]

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Other answers:

u mean\[\frac{ 1 }{ 27 }=9^{7x+3}\]
i get 3^3?
yes, sorry
np :) ... yeah u r close but note that\[\frac{1}{27}=\frac{1}{3^3}=3^{-3}\]
oh of course! got that..
and then make the 9 = 3^2?
yeah...quite right
\[3^{-3}=3^{14x+6}\]
Right...
now go for solving for x
\[-\frac{ 9 }{ 14 }\]
you rock! thanks for the help.. the -3 is what got me! :)
yw :)

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