haileyy0401
How do you simplify an trigonometric equation like the following?



This Question is Closed

haileyy0401
Best Response
You've already chosen the best response.
0
dw:1355951638823:dw

hubertH
Best Response
You've already chosen the best response.
0
u need ur identities, from s\[\sin^2+\cos ^2=1\] make sin the subject of the formula

hubertH
Best Response
You've already chosen the best response.
0
\[\frac{ \sin ^2\theta }{ 1\cos \theta }
=\frac{ 1\cos ^2\theta }{ 1\cos \theta }
=\frac{( 1\cos \theta)(1+\cos \theta) }{ (1\cos \theta) }\]

haileyy0401
Best Response
You've already chosen the best response.
0
How do you get sin theta squared is equal to (1cos)(1+cos)?

hubertH
Best Response
You've already chosen the best response.
0
do u know this identity?\[\sin ^2\theta+\cos ^2\theta=1\]

haileyy0401
Best Response
You've already chosen the best response.
0
yes.

hubertH
Best Response
You've already chosen the best response.
0
now try make sin^2 the subvject of the formula what do u get?

hubertH
Best Response
You've already chosen the best response.
0
u'll get a difference of two squares which i'm sure u can solve

haileyy0401
Best Response
You've already chosen the best response.
0
you would get sin^2 theta= 1cos^2 theta?

hubertH
Best Response
You've already chosen the best response.
0
yes
can u now see that 1 cos^2 theta is a fifference of two squares?

hubertH
Best Response
You've already chosen the best response.
0
1cos^2=(1cos)(1+cos)