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How do you simplify an trigonometric equation like the following?
 one year ago
 one year ago
How do you simplify an trigonometric equation like the following?
 one year ago
 one year ago

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haileyy0401Best ResponseYou've already chosen the best response.0
dw:1355951638823:dw
 one year ago

hubertHBest ResponseYou've already chosen the best response.0
u need ur identities, from s\[\sin^2+\cos ^2=1\] make sin the subject of the formula
 one year ago

hubertHBest ResponseYou've already chosen the best response.0
\[\frac{ \sin ^2\theta }{ 1\cos \theta } =\frac{ 1\cos ^2\theta }{ 1\cos \theta } =\frac{( 1\cos \theta)(1+\cos \theta) }{ (1\cos \theta) }\]
 one year ago

haileyy0401Best ResponseYou've already chosen the best response.0
How do you get sin theta squared is equal to (1cos)(1+cos)?
 one year ago

hubertHBest ResponseYou've already chosen the best response.0
do u know this identity?\[\sin ^2\theta+\cos ^2\theta=1\]
 one year ago

hubertHBest ResponseYou've already chosen the best response.0
now try make sin^2 the subvject of the formula what do u get?
 one year ago

hubertHBest ResponseYou've already chosen the best response.0
u'll get a difference of two squares which i'm sure u can solve
 one year ago

haileyy0401Best ResponseYou've already chosen the best response.0
you would get sin^2 theta= 1cos^2 theta?
 one year ago

hubertHBest ResponseYou've already chosen the best response.0
yes can u now see that 1 cos^2 theta is a fifference of two squares?
 one year ago

hubertHBest ResponseYou've already chosen the best response.0
1cos^2=(1cos)(1+cos)
 one year ago
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