anonymous
  • anonymous
How do you simplify an trigonometric equation like the following?
Trigonometry
chestercat
  • chestercat
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anonymous
  • anonymous
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anonymous
  • anonymous
u need ur identities, from s\[\sin^2+\cos ^2=1\] make sin the subject of the formula
anonymous
  • anonymous
\[\frac{ \sin ^2\theta }{ 1-\cos \theta } =\frac{ 1-\cos ^2\theta }{ 1-\cos \theta } =\frac{( 1-\cos \theta)(1+\cos \theta) }{ (1-\cos \theta) }\]

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anonymous
  • anonymous
How do you get sin theta squared is equal to (1-cos)(1+cos)?
anonymous
  • anonymous
do u know this identity?\[\sin ^2\theta+\cos ^2\theta=1\]
anonymous
  • anonymous
yes.
anonymous
  • anonymous
now try make sin^2 the subvject of the formula what do u get?
anonymous
  • anonymous
u'll get a difference of two squares which i'm sure u can solve
anonymous
  • anonymous
you would get sin^2 theta= 1-cos^2 theta?
anonymous
  • anonymous
yes can u now see that 1- cos^2 theta is a fifference of two squares?
anonymous
  • anonymous
1-cos^2=(1-cos)(1+cos)

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