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haileyy0401

  • 2 years ago

How do you simplify an trigonometric equation like the following?

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  1. haileyy0401
    • 2 years ago
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    |dw:1355951638823:dw|

  2. hubertH
    • 2 years ago
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    u need ur identities, from s\[\sin^2+\cos ^2=1\] make sin the subject of the formula

  3. hubertH
    • 2 years ago
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    \[\frac{ \sin ^2\theta }{ 1-\cos \theta } =\frac{ 1-\cos ^2\theta }{ 1-\cos \theta } =\frac{( 1-\cos \theta)(1+\cos \theta) }{ (1-\cos \theta) }\]

  4. haileyy0401
    • 2 years ago
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    How do you get sin theta squared is equal to (1-cos)(1+cos)?

  5. hubertH
    • 2 years ago
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    do u know this identity?\[\sin ^2\theta+\cos ^2\theta=1\]

  6. haileyy0401
    • 2 years ago
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    yes.

  7. hubertH
    • 2 years ago
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    now try make sin^2 the subvject of the formula what do u get?

  8. hubertH
    • 2 years ago
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    u'll get a difference of two squares which i'm sure u can solve

  9. haileyy0401
    • 2 years ago
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    you would get sin^2 theta= 1-cos^2 theta?

  10. hubertH
    • 2 years ago
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    yes can u now see that 1- cos^2 theta is a fifference of two squares?

  11. hubertH
    • 2 years ago
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    1-cos^2=(1-cos)(1+cos)

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