anonymous
  • anonymous
Find the lengths of the missing sides of the triangle: 17 on the hypotnuse, x+7 on the adjacent side, and x on the opposite side.
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
(x+7)^2 + x^2= 17^2. You can solve it yourself?
anonymous
  • anonymous
are you sure we use a^2+b^2=c^2?
anonymous
  • anonymous
Yes, the hypothenuse is the longest side of a right angle triangle. Unless I forgot my basic geometry.

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
thats true, but idk what it would be then?
anonymous
  • anonymous
foil the x+7?
anonymous
  • anonymous
yes, simplify the x+7, you will get a quadratic, either find its root by factoring or use the quadratic formula
anonymous
  • anonymous
so the root is -7?
anonymous
  • anonymous
it can't be a negative. I got 6. ( I did it really quickly so you,d have to check). But a measurement cannot be negatie. ever.
anonymous
  • anonymous
oh I see.how did you do it?
anonymous
  • anonymous
(x+7)(x+7) + x^2 = 17^2. Bring all to one side it will give you 2(x^2+14x-120). One of your zero will b -20 the other will be 6
anonymous
  • anonymous
this is what I got
anonymous
  • anonymous
17^2 = [x+7]^2 + x^2 289 = x^2 + 14x + 49 + x^2 2x^2 + 14x - 240 = 0 divide by 2 x^2 + 7x - 120 = 0 factor [x + 15][x - 8] = 0
anonymous
  • anonymous
so opposite side = 8 adjacent side = 15
anonymous
  • anonymous
is that correct?
anonymous
  • anonymous
yes that should be it, if what I calculated is right.
anonymous
  • anonymous
oh wait wait, with yoru calculations you get x= 8, you have to plug it in x+7 therefore 8+7 = 15. Don't forget you had an initial equation
anonymous
  • anonymous
yeah x=8 because when I set x+15=0 I get a negative 15. so I plug 8 back into x+7?
anonymous
  • anonymous
so my opposite side is just 8? and adjacent is 15?
anonymous
  • anonymous
yes thats it you got it. :)
anonymous
  • anonymous
okay yay! thanks so much for your help :)

Looking for something else?

Not the answer you are looking for? Search for more explanations.