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Find the lengths of the missing sides of the triangle: 17 on the hypotnuse, x+7 on the adjacent side, and x on the opposite side.

Mathematics
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(x+7)^2 + x^2= 17^2. You can solve it yourself?
are you sure we use a^2+b^2=c^2?
Yes, the hypothenuse is the longest side of a right angle triangle. Unless I forgot my basic geometry.

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Other answers:

thats true, but idk what it would be then?
foil the x+7?
yes, simplify the x+7, you will get a quadratic, either find its root by factoring or use the quadratic formula
so the root is -7?
it can't be a negative. I got 6. ( I did it really quickly so you,d have to check). But a measurement cannot be negatie. ever.
oh I see.how did you do it?
(x+7)(x+7) + x^2 = 17^2. Bring all to one side it will give you 2(x^2+14x-120). One of your zero will b -20 the other will be 6
this is what I got
17^2 = [x+7]^2 + x^2 289 = x^2 + 14x + 49 + x^2 2x^2 + 14x - 240 = 0 divide by 2 x^2 + 7x - 120 = 0 factor [x + 15][x - 8] = 0
so opposite side = 8 adjacent side = 15
is that correct?
yes that should be it, if what I calculated is right.
oh wait wait, with yoru calculations you get x= 8, you have to plug it in x+7 therefore 8+7 = 15. Don't forget you had an initial equation
yeah x=8 because when I set x+15=0 I get a negative 15. so I plug 8 back into x+7?
so my opposite side is just 8? and adjacent is 15?
yes thats it you got it. :)
okay yay! thanks so much for your help :)

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