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Sunshine447

  • 3 years ago

I've been stuck on these for a while.... Posting pictures

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  1. Sunshine447
    • 3 years ago
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  2. Sunshine447
    • 3 years ago
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    @UnkleRhaukus

  3. Sunshine447
    • 3 years ago
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    @AccessDenied

  4. BluFoot
    • 3 years ago
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    Ok you might want to draw them as lines, that helps me anyway. I'll do 45 c and 46 b for you. |dw:1355956901226:dw| 1. Find the longest chain. 2. Look for unsaturations in this chain. 3. Look for substituents on this chain. 45c: The longest chain is 4, which means "but". There are no unsaturations, which means "ane". There is a methyl group. Start counting from the side closer to the methyl group. This makes it on the 2nd carbon. So the name is 2-methylbutane. 46b: The longest chain is 5, which means "pent". There is an unsaturation: a double bond, which means "ene". So start counting from the side closer to the unsaturation (if there were a substituent, the unsaturation takes priority). This makes the double bond at the second carbon. There are no substituents. So the name is pent-2-ene.

  5. BluFoot
    • 3 years ago
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    I recommend the khan academy videos if you're having trouble with this. http://www.khanacademy.org/science/organic-chemistry/v/more-organic-chemistry-naming-examples-1

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