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Sunshine447
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I've been stuck on these for a while.... Posting pictures
 one year ago
 one year ago
Sunshine447 Group Title
I've been stuck on these for a while.... Posting pictures
 one year ago
 one year ago

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Sunshine447 Group TitleBest ResponseYou've already chosen the best response.0
@UnkleRhaukus
 one year ago

Sunshine447 Group TitleBest ResponseYou've already chosen the best response.0
@AccessDenied
 one year ago

BluFoot Group TitleBest ResponseYou've already chosen the best response.0
Ok you might want to draw them as lines, that helps me anyway. I'll do 45 c and 46 b for you. dw:1355956901226:dw 1. Find the longest chain. 2. Look for unsaturations in this chain. 3. Look for substituents on this chain. 45c: The longest chain is 4, which means "but". There are no unsaturations, which means "ane". There is a methyl group. Start counting from the side closer to the methyl group. This makes it on the 2nd carbon. So the name is 2methylbutane. 46b: The longest chain is 5, which means "pent". There is an unsaturation: a double bond, which means "ene". So start counting from the side closer to the unsaturation (if there were a substituent, the unsaturation takes priority). This makes the double bond at the second carbon. There are no substituents. So the name is pent2ene.
 one year ago

BluFoot Group TitleBest ResponseYou've already chosen the best response.0
I recommend the khan academy videos if you're having trouble with this. http://www.khanacademy.org/science/organicchemistry/v/moreorganicchemistrynamingexamples1
 one year ago
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