A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 4 years ago
I've been stuck on these for a while.... Posting pictures
anonymous
 4 years ago
I've been stuck on these for a while.... Posting pictures

This Question is Closed

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Ok you might want to draw them as lines, that helps me anyway. I'll do 45 c and 46 b for you. dw:1355956901226:dw 1. Find the longest chain. 2. Look for unsaturations in this chain. 3. Look for substituents on this chain. 45c: The longest chain is 4, which means "but". There are no unsaturations, which means "ane". There is a methyl group. Start counting from the side closer to the methyl group. This makes it on the 2nd carbon. So the name is 2methylbutane. 46b: The longest chain is 5, which means "pent". There is an unsaturation: a double bond, which means "ene". So start counting from the side closer to the unsaturation (if there were a substituent, the unsaturation takes priority). This makes the double bond at the second carbon. There are no substituents. So the name is pent2ene.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I recommend the khan academy videos if you're having trouble with this. http://www.khanacademy.org/science/organicchemistry/v/moreorganicchemistrynamingexamples1
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.