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haileyy0401
How do you figure out the csc and sec? For a standard-position angle determined by the point (x, y), what are the values of the trigonometric functions? For the point (9, 12), find csc theta and sec theta
well, If we draw these points on the graph, it would give us a right-angled triangle and then we may apply pythagoras' theorem to get "sin (theta)" & "cos (theta)" and "sec (theta) = 1/cos(theta)" & "csc(theta) = 1/sin(theta)". From the points (as it makes a right-angled triangle), we know Suppose, a = horizontal side of triangle, b = verticle, and c = longest side (or diagonal) So, a = 9, b = 12 and applying pythagoras' theorem now, (the theorem is c^2 = a^2 + b^2) we get c^2 = 9^2 + 12^2 c^2 = 81 + 144 c^2 = 225 c = 15. So, now the values of the sides of the triangle are a = 9, b = 12, c = 15 and, If "theta" is the angle between a & b, then cos(theta) = 15/12 = 5/4 and, sin(theta) = 15/9 = 5/3 So, sec(theta) = 1/cos(theta) = 1/(5/4) = 4/5 csc(theta) = 1/sin(theta) = 1/(5/3) = 3/5 That's the answer. HTH :)
Is that the correct answer? can u verify?
I will be able to verify in one minute.
Thats not one of the choices.... a. csc = 15/12 sec = 15/9 b. csc = 15/12 sec = 12/15 c. csc = 9/15 sec = 12/15 d. csc = 9/12 sec = 9/15
oh did you mean csc and sec? instead of cos and sin?
Option C is the correct answer