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 2 years ago
In the first problem set, Problem 1b2 part c, the solution page does not show work. I've been working this problem over and over again and keep getting the same thing (7b^2 / 32) and cannot figure out how they got (b^2 / 64) instead. Can anyone work out a solution?
 2 years ago
In the first problem set, Problem 1b2 part c, the solution page does not show work. I've been working this problem over and over again and keep getting the same thing (7b^2 / 32) and cannot figure out how they got (b^2 / 64) instead. Can anyone work out a solution?

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beginnersmind
 2 years ago
Best ResponseYou've already chosen the best response.0b^2/64 is correct. First take the derivative of s(t) to find the time of the maximum height. s'(t) = b32t solving for 0 gives t=32/b. So the tennis ball is at maximum height at t = 32/b. To see how high it is at 32/b just plug it back to the expression s(t).

kozmikvoid
 2 years ago
Best ResponseYou've already chosen the best response.1Duckbill  I see how you're getting your answer. You are calculating 16t^2 incorrectly. It's technically 16(t^2), which equals 16(b^2/1024), which equals b^2/64. You end up with b^2/32b^2/64, which equals b^2/64.
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