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Sounds like you know what you are doing .... What's the problem you are having?
Well, I had help with that part, but I can't figure out what to do next. I tried using my textbook, but it was a bit confusing, because they showed you what to do, but didn't explain it.
Ok, first let's distribute that -(-6x+12) Can you do that?
-6x + -72?
Think of it this way: (-)(-6x) & (-)(12)
Because negative times negative equals a positive 6x + -12?
yes, very good so we have 6x-12+3x=6 What will you do next?
Add 6x and 3x?
correct 9x-12=6 now what?
Substitute for y from the other equation?
Let's try to solve for x.
Sorry, I was looking at my textbook, and thought that we were onto that step.
:-) That's ok.
Okay, so how would I go about solving for x? Also, thank you for the medal.
We have x on one side, can we get non x-values on the other side?
You would add 12 + 6? Then get 18, divided by 9x would equal 2.
Excellent: So x=2
What are you going to do with that x=2?
You still there?
Substitute 2 for x in either equation and solve for y? Sorry, my computer is slow sometimes.
Heh I Understand. You are correct, good job!
Thank you! So, -y + 3(2) + 6.
So, -y + 6 = 6.
What would I do next?
same that you did when you had 9x-12=6 and solved for x. now we are going to it for y
6 - 6 = 0 So y, would be 0?
That is correct.
Then I would substitute 0for y, and get 0 + 6 = 6.
Correct: So your Answer is: X=2, y=0
As long as you get a correct statement when you plug them both back in, like you showed 6=6 and not get something like 7=6, then we would have a problem.
Okay, thank you some much for your help. If I could give you more than one medal I would.
Thank you, It is nice to meet someone who wants to work out the problems and not just demand an answer.
I get what you mean, you are a very good teacher by the way.