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swin2013 Group TitleBest ResponseYou've already chosen the best response.0
\[\lim x> 0 \frac{ 3\sin4x }{ \sin3x }\]
 one year ago

swin2013 Group TitleBest ResponseYou've already chosen the best response.0
sorry that's limit approaching zero lol
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.2
so do u know the basic limit of sin x/x =... ?
 one year ago

swin2013 Group TitleBest ResponseYou've already chosen the best response.0
yes it's = 1?
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.2
so, according to that formula , u need the denominator same as angle of sin. so, multiply and divide by 4x in numerator and multiply and divide by 3x in denominator
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.2
\(\huge \lim \limits_{x> 0} \frac{ 3 \frac{4x.\sin4x}{4x} }{ 3x.\frac{\sin3x}{3x} }\)
 one year ago

zepdrix Group TitleBest ResponseYou've already chosen the best response.2
That seems like a bit of overkill hart :o don't you just need 4x/4x?
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.2
yeah, thats correct, but i wanted to brig out the point that whenever you see sin ax , multiply and divide by ax
 one year ago

swin2013 Group TitleBest ResponseYou've already chosen the best response.0
well can i bring out what's in the denominator first?
 one year ago

swin2013 Group TitleBest ResponseYou've already chosen the best response.0
by multiplying the denominator by 3?
 one year ago

zepdrix Group TitleBest ResponseYou've already chosen the best response.2
\[\large \lim_{x \rightarrow 0}\frac{4x}{4x}\frac{3\sin4x}{\sin3x} \quad = \quad 4\lim_{x \rightarrow 0}\frac{\sin4x}{4x}\frac{3x}{\sin3x}\]
 one year ago

zepdrix Group TitleBest ResponseYou've already chosen the best response.2
Oh ok i see what you meant :)
 one year ago

zepdrix Group TitleBest ResponseYou've already chosen the best response.2
The upside down one will also give you 1 swin.
 one year ago

zepdrix Group TitleBest ResponseYou've already chosen the best response.2
It might make more sense if you look at the way hart wrote it out.
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.2
yeah, lim x>0 x/sin x also equals 1
 one year ago

swin2013 Group TitleBest ResponseYou've already chosen the best response.0
chyea I'm trying to find a quicker way to solve for my final hahaha! i initially split them up so it was 3sin4x/1 * 1/sin3x. I'm not sure if that's legal
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.2
yeah, its legal step, but you will still need the form sin x/x so you need to multiply and divide by the angle of sin
 one year ago

swin2013 Group TitleBest ResponseYou've already chosen the best response.0
So it will be 4?
 one year ago

zepdrix Group TitleBest ResponseYou've already chosen the best response.2
\[\large \color{green}{Good}\quad \color{blue}{job!}\]
 one year ago

swin2013 Group TitleBest ResponseYou've already chosen the best response.0
Lol thanks guys!! A couple of hours till I take my final :)
 one year ago

zepdrix Group TitleBest ResponseYou've already chosen the best response.2
Oooo exciting! :O keep cramming. Sleep is good also.
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.2
do u need to show steps ?
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.2
because if you do, while taking the limit, you also need to show that 3x>0 and 4x> 0
 one year ago

swin2013 Group TitleBest ResponseYou've already chosen the best response.0
Probably not, because I think it's just simplifying it to make sinx/x = 1. But I understand how you solved it, Thanks for the review :)
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.2
ok, welcome ^_^
 one year ago
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