A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 3 years ago
Determine the limit
anonymous
 3 years ago
Determine the limit

This Question is Closed

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0\[\lim x> 0 \frac{ 3\sin4x }{ \sin3x }\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0sorry that's limit approaching zero lol

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.2so do u know the basic limit of sin x/x =... ?

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.2so, according to that formula , u need the denominator same as angle of sin. so, multiply and divide by 4x in numerator and multiply and divide by 3x in denominator

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.2\(\huge \lim \limits_{x> 0} \frac{ 3 \frac{4x.\sin4x}{4x} }{ 3x.\frac{\sin3x}{3x} }\)

zepdrix
 3 years ago
Best ResponseYou've already chosen the best response.2That seems like a bit of overkill hart :o don't you just need 4x/4x?

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.2yeah, thats correct, but i wanted to brig out the point that whenever you see sin ax , multiply and divide by ax

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0well can i bring out what's in the denominator first?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0by multiplying the denominator by 3?

zepdrix
 3 years ago
Best ResponseYou've already chosen the best response.2\[\large \lim_{x \rightarrow 0}\frac{4x}{4x}\frac{3\sin4x}{\sin3x} \quad = \quad 4\lim_{x \rightarrow 0}\frac{\sin4x}{4x}\frac{3x}{\sin3x}\]

zepdrix
 3 years ago
Best ResponseYou've already chosen the best response.2Oh ok i see what you meant :)

zepdrix
 3 years ago
Best ResponseYou've already chosen the best response.2The upside down one will also give you 1 swin.

zepdrix
 3 years ago
Best ResponseYou've already chosen the best response.2It might make more sense if you look at the way hart wrote it out.

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.2yeah, lim x>0 x/sin x also equals 1

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0chyea I'm trying to find a quicker way to solve for my final hahaha! i initially split them up so it was 3sin4x/1 * 1/sin3x. I'm not sure if that's legal

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.2yeah, its legal step, but you will still need the form sin x/x so you need to multiply and divide by the angle of sin

zepdrix
 3 years ago
Best ResponseYou've already chosen the best response.2\[\large \color{green}{Good}\quad \color{blue}{job!}\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Lol thanks guys!! A couple of hours till I take my final :)

zepdrix
 3 years ago
Best ResponseYou've already chosen the best response.2Oooo exciting! :O keep cramming. Sleep is good also.

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.2do u need to show steps ?

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.2because if you do, while taking the limit, you also need to show that 3x>0 and 4x> 0

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Probably not, because I think it's just simplifying it to make sinx/x = 1. But I understand how you solved it, Thanks for the review :)
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.