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swin2013
 3 years ago
Determine the limit
swin2013
 3 years ago
Determine the limit

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swin2013
 3 years ago
Best ResponseYou've already chosen the best response.0\[\lim x> 0 \frac{ 3\sin4x }{ \sin3x }\]

swin2013
 3 years ago
Best ResponseYou've already chosen the best response.0sorry that's limit approaching zero lol

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.2so do u know the basic limit of sin x/x =... ?

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.2so, according to that formula , u need the denominator same as angle of sin. so, multiply and divide by 4x in numerator and multiply and divide by 3x in denominator

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.2\(\huge \lim \limits_{x> 0} \frac{ 3 \frac{4x.\sin4x}{4x} }{ 3x.\frac{\sin3x}{3x} }\)

zepdrix
 3 years ago
Best ResponseYou've already chosen the best response.2That seems like a bit of overkill hart :o don't you just need 4x/4x?

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.2yeah, thats correct, but i wanted to brig out the point that whenever you see sin ax , multiply and divide by ax

swin2013
 3 years ago
Best ResponseYou've already chosen the best response.0well can i bring out what's in the denominator first?

swin2013
 3 years ago
Best ResponseYou've already chosen the best response.0by multiplying the denominator by 3?

zepdrix
 3 years ago
Best ResponseYou've already chosen the best response.2\[\large \lim_{x \rightarrow 0}\frac{4x}{4x}\frac{3\sin4x}{\sin3x} \quad = \quad 4\lim_{x \rightarrow 0}\frac{\sin4x}{4x}\frac{3x}{\sin3x}\]

zepdrix
 3 years ago
Best ResponseYou've already chosen the best response.2Oh ok i see what you meant :)

zepdrix
 3 years ago
Best ResponseYou've already chosen the best response.2The upside down one will also give you 1 swin.

zepdrix
 3 years ago
Best ResponseYou've already chosen the best response.2It might make more sense if you look at the way hart wrote it out.

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.2yeah, lim x>0 x/sin x also equals 1

swin2013
 3 years ago
Best ResponseYou've already chosen the best response.0chyea I'm trying to find a quicker way to solve for my final hahaha! i initially split them up so it was 3sin4x/1 * 1/sin3x. I'm not sure if that's legal

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.2yeah, its legal step, but you will still need the form sin x/x so you need to multiply and divide by the angle of sin

zepdrix
 3 years ago
Best ResponseYou've already chosen the best response.2\[\large \color{green}{Good}\quad \color{blue}{job!}\]

swin2013
 3 years ago
Best ResponseYou've already chosen the best response.0Lol thanks guys!! A couple of hours till I take my final :)

zepdrix
 3 years ago
Best ResponseYou've already chosen the best response.2Oooo exciting! :O keep cramming. Sleep is good also.

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.2do u need to show steps ?

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.2because if you do, while taking the limit, you also need to show that 3x>0 and 4x> 0

swin2013
 3 years ago
Best ResponseYou've already chosen the best response.0Probably not, because I think it's just simplifying it to make sinx/x = 1. But I understand how you solved it, Thanks for the review :)
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