Open study

is now brainly

With Brainly you can:

  • Get homework help from millions of students and moderators
  • Learn how to solve problems with step-by-step explanations
  • Share your knowledge and earn points by helping other students
  • Learn anywhere, anytime with the Brainly app!

A community for students.

- Optimization problem - A rectangle is inscribed with its base on the x-axis and its upper corners on the parabola . What are the dimensions of such a rectangle with the greatest possible area?

Mathematics
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Join Brainly to access

this expert answer

SEE EXPERT ANSWER

To see the expert answer you'll need to create a free account at Brainly

oh sorry the parabola is y=5-x^2
I was thinking find the 0 for the parabola, and because it touches the 2 upper part I get sqrt(5) and -sqrt(5) being the length for y and I can ind the length in x because those 2 y are the distance between 2 cornor that is the length?
Since the rectangular inscribed in the parabola: it's length is symmetry x+ x => A = 2x y = 2x ( 5 - x²)

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

oh. inscribed in, so i had it wrong... so you don't have any constraint in this problem...?
I think the range of parabola is the constraint, just get the concept first!
Well I usually go about these problem by finding my constraint then the equation I need to solve, but I couldn't do so. But when you say A=x(5-x^2) and so I take the derivative of both side and I should get x(5-2x) + (5-x^2) = A'(x) 5x-2x^2+5-x^2 -3x^2+5x+5 and then use quadratic to find my x ?
A = 2x ( 5 - x²) = -2x³ + 10x ->A' = -6x² + 10 = 0 => x = √ 5/3
but wait, why did you mention x + x being symmetrical? and I asked about the constraint because, don't you need one to do an optimization problem?
Did you sketch the rectangular inscribes in the parabola, you'll see the constraint -√ 5 ≤ x ≤ √5, 0 ≤ y ≤ 5

Not the answer you are looking for?

Search for more explanations.

Ask your own question