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For session 2 dealing with derivatives as a rate of change. In the problem pdf for question 2. Taking f'(10) why do we automatically assume to take f(11) to find the value of 175 in order to validate the $40 dollar decrease?
 one year ago
 one year ago
For session 2 dealing with derivatives as a rate of change. In the problem pdf for question 2. Taking f'(10) why do we automatically assume to take f(11) to find the value of 175 in order to validate the $40 dollar decrease?
 one year ago
 one year ago

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MattBenjaminsBest ResponseYou've already chosen the best response.0
Hello, f'(10) is the rate at which the bank balance is changing during the month October (the tenth month). f(10) is the actual balance in October and f(11) the balance in November. By subtracting f(10) from f(11) you can simply check how much the balance has changed from October to November. In this case: \[f(11)f(10) = 175  220 = 45\] Which is close enough to 40 to verify the rate of change found by taking f'(10). On a side note. The solution pdf suggest trying f(10)f(11) to check the change but that's a bad idea. The difference will still be 45 but it will be a positive number when the actual change has been a decrease. As a rule, subtract function values for smaller x's from function values for larger x's to not just get a change, but also whether that change has been positive or negative.
 one year ago
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