i want to graph 3csc2x but I dont know how!! can someone help me with steps!??

- anonymous

i want to graph 3csc2x but I dont know how!! can someone help me with steps!??

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- katieb

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- AravindG

do u knw the graph of cosec x?

- Kainui

One way might be to try rewriting 3csc(2x) as 3/sin(2x).
Then from here, mark on your graph where one period should end and where the amplitude should be. Since it's 1/sin it will be "upside down"
Look at this picture to give yourself some help along the way so that next time you can see.
http://www.wolframalpha.com/input/?i=%203csc(2x)&t=crmtb01
The main points to hit when graphing any trig function are what it looks like at 0, T/4, T/2, 3T/2, and T, since it repeats after that and you can kind of "guess" by filling in the points between where the curve should look like.

- anonymous

i know that cscx = 1/sinx

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## More answers

- anonymous

so if i put that function... 3/sin(2x)?

- AravindG

i can help with an alternate solution ..but for that you need to answer my queries

- anonymous

the graph of csc ..yes i do know what it is!

- Kainui

Find the amplitude and period.

- AravindG

well thats great...now what you need to understand is that the graph of cosec 2x will be same as cosec x only difference is that we have to minimize the graph to t=pi

- AravindG

let me show u how i do that for sin 2x

- AravindG

|dw:1355991064248:dw|

- AravindG

did you get that ?

- anonymous

sin2x makes the half of sinx

- AravindG

yep similiar is what happens for cosec 2x

- AravindG

its like bending a spring to half its normal position from one side

- anonymous

okay!

- AravindG

now ...we are 80% over !

- anonymous

ok!!

- AravindG

well next step is to increase the magnitude of cosec 2x 3 times

- anonymous

does that mean the maximum is at 3??

- AravindG

think again :)

- anonymous

i mean min 3, max3

- AravindG

yepp !!

- anonymous

okay...so what do i do next?

- AravindG

we actually dont need pencil or paper just our mind to visualize this !!

- AravindG

we are done !! this is ur graph !!

- anonymous

oh yeah!!! omgsh thank you so much!!! wait im gonna do a quick sketch

- AravindG

well see hw elegantmethod it is when compared to normal working that we do mechanically (see kainnui's re[ly)

- anonymous

|dw:1355991527707:dw|

- AravindG

mark angles pls

- anonymous

|dw:1355991626300:dw|

- anonymous

is it correct?

- AravindG

exactlyy !! well done !!

- anonymous

Ah thank you so much!!! you're an amzing teacher!!

- AravindG

you did it yourself !! cngrts!!

- AravindG

remember:always use ur visualization power as the first resort to solve math problems..it really simplifies ur work !! good luck!

- Kainui

Yeah, awesome, you're a quick learner Isugano.

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