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AravindG
 2 years ago
Best ResponseYou've already chosen the best response.2do u knw the graph of cosec x?

Kainui
 2 years ago
Best ResponseYou've already chosen the best response.0One way might be to try rewriting 3csc(2x) as 3/sin(2x). Then from here, mark on your graph where one period should end and where the amplitude should be. Since it's 1/sin it will be "upside down" Look at this picture to give yourself some help along the way so that next time you can see. http://www.wolframalpha.com/input/?i=%203csc(2x)&t=crmtb01 The main points to hit when graphing any trig function are what it looks like at 0, T/4, T/2, 3T/2, and T, since it repeats after that and you can kind of "guess" by filling in the points between where the curve should look like.

lsugano
 2 years ago
Best ResponseYou've already chosen the best response.0i know that cscx = 1/sinx

lsugano
 2 years ago
Best ResponseYou've already chosen the best response.0so if i put that function... 3/sin(2x)?

AravindG
 2 years ago
Best ResponseYou've already chosen the best response.2i can help with an alternate solution ..but for that you need to answer my queries

lsugano
 2 years ago
Best ResponseYou've already chosen the best response.0the graph of csc ..yes i do know what it is!

Kainui
 2 years ago
Best ResponseYou've already chosen the best response.0Find the amplitude and period.

AravindG
 2 years ago
Best ResponseYou've already chosen the best response.2well thats great...now what you need to understand is that the graph of cosec 2x will be same as cosec x only difference is that we have to minimize the graph to t=pi

AravindG
 2 years ago
Best ResponseYou've already chosen the best response.2let me show u how i do that for sin 2x

lsugano
 2 years ago
Best ResponseYou've already chosen the best response.0sin2x makes the half of sinx

AravindG
 2 years ago
Best ResponseYou've already chosen the best response.2yep similiar is what happens for cosec 2x

AravindG
 2 years ago
Best ResponseYou've already chosen the best response.2its like bending a spring to half its normal position from one side

AravindG
 2 years ago
Best ResponseYou've already chosen the best response.2now ...we are 80% over !

AravindG
 2 years ago
Best ResponseYou've already chosen the best response.2well next step is to increase the magnitude of cosec 2x 3 times

lsugano
 2 years ago
Best ResponseYou've already chosen the best response.0does that mean the maximum is at 3??

lsugano
 2 years ago
Best ResponseYou've already chosen the best response.0okay...so what do i do next?

AravindG
 2 years ago
Best ResponseYou've already chosen the best response.2we actually dont need pencil or paper just our mind to visualize this !!

AravindG
 2 years ago
Best ResponseYou've already chosen the best response.2we are done !! this is ur graph !!

lsugano
 2 years ago
Best ResponseYou've already chosen the best response.0oh yeah!!! omgsh thank you so much!!! wait im gonna do a quick sketch

AravindG
 2 years ago
Best ResponseYou've already chosen the best response.2well see hw elegantmethod it is when compared to normal working that we do mechanically (see kainnui's re[ly)

AravindG
 2 years ago
Best ResponseYou've already chosen the best response.2exactlyy !! well done !!

lsugano
 2 years ago
Best ResponseYou've already chosen the best response.0Ah thank you so much!!! you're an amzing teacher!!

AravindG
 2 years ago
Best ResponseYou've already chosen the best response.2you did it yourself !! cngrts!!

AravindG
 2 years ago
Best ResponseYou've already chosen the best response.2remember:always use ur visualization power as the first resort to solve math problems..it really simplifies ur work !! good luck!

Kainui
 2 years ago
Best ResponseYou've already chosen the best response.0Yeah, awesome, you're a quick learner Isugano.
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