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lsugano Group Title

i want to graph 3csc2x but I dont know how!! can someone help me with steps!??

  • one year ago
  • one year ago

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  1. AravindG Group Title
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    do u knw the graph of cosec x?

    • one year ago
  2. Kainui Group Title
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    One way might be to try rewriting 3csc(2x) as 3/sin(2x). Then from here, mark on your graph where one period should end and where the amplitude should be. Since it's 1/sin it will be "upside down" Look at this picture to give yourself some help along the way so that next time you can see. http://www.wolframalpha.com/input/?i=%203csc(2x)&t=crmtb01 The main points to hit when graphing any trig function are what it looks like at 0, T/4, T/2, 3T/2, and T, since it repeats after that and you can kind of "guess" by filling in the points between where the curve should look like.

    • one year ago
  3. lsugano Group Title
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    i know that cscx = 1/sinx

    • one year ago
  4. lsugano Group Title
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    so if i put that function... 3/sin(2x)?

    • one year ago
  5. AravindG Group Title
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    i can help with an alternate solution ..but for that you need to answer my queries

    • one year ago
  6. lsugano Group Title
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    the graph of csc ..yes i do know what it is!

    • one year ago
  7. Kainui Group Title
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    Find the amplitude and period.

    • one year ago
  8. AravindG Group Title
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    well thats great...now what you need to understand is that the graph of cosec 2x will be same as cosec x only difference is that we have to minimize the graph to t=pi

    • one year ago
  9. AravindG Group Title
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    let me show u how i do that for sin 2x

    • one year ago
  10. AravindG Group Title
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    |dw:1355991064248:dw|

    • one year ago
  11. AravindG Group Title
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    did you get that ?

    • one year ago
  12. lsugano Group Title
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    sin2x makes the half of sinx

    • one year ago
  13. AravindG Group Title
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    yep similiar is what happens for cosec 2x

    • one year ago
  14. AravindG Group Title
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    its like bending a spring to half its normal position from one side

    • one year ago
  15. lsugano Group Title
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    okay!

    • one year ago
  16. AravindG Group Title
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    now ...we are 80% over !

    • one year ago
  17. lsugano Group Title
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    ok!!

    • one year ago
  18. AravindG Group Title
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    well next step is to increase the magnitude of cosec 2x 3 times

    • one year ago
  19. lsugano Group Title
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    does that mean the maximum is at 3??

    • one year ago
  20. AravindG Group Title
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    think again :)

    • one year ago
  21. lsugano Group Title
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    i mean min 3, max3

    • one year ago
  22. AravindG Group Title
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    yepp !!

    • one year ago
  23. lsugano Group Title
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    okay...so what do i do next?

    • one year ago
  24. AravindG Group Title
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    we actually dont need pencil or paper just our mind to visualize this !!

    • one year ago
  25. AravindG Group Title
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    we are done !! this is ur graph !!

    • one year ago
  26. lsugano Group Title
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    oh yeah!!! omgsh thank you so much!!! wait im gonna do a quick sketch

    • one year ago
  27. AravindG Group Title
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    well see hw elegantmethod it is when compared to normal working that we do mechanically (see kainnui's re[ly)

    • one year ago
  28. lsugano Group Title
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    |dw:1355991527707:dw|

    • one year ago
  29. AravindG Group Title
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    mark angles pls

    • one year ago
  30. lsugano Group Title
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    |dw:1355991626300:dw|

    • one year ago
  31. lsugano Group Title
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    is it correct?

    • one year ago
  32. AravindG Group Title
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    exactlyy !! well done !!

    • one year ago
  33. lsugano Group Title
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    Ah thank you so much!!! you're an amzing teacher!!

    • one year ago
  34. AravindG Group Title
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    you did it yourself !! cngrts!!

    • one year ago
  35. AravindG Group Title
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    remember:always use ur visualization power as the first resort to solve math problems..it really simplifies ur work !! good luck!

    • one year ago
  36. Kainui Group Title
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    Yeah, awesome, you're a quick learner Isugano.

    • one year ago
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