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anonymous
 3 years ago
answers !!!!
qs 6
a) and b) L/(rw+rl)
c and d) go to sandbox, make the circuit, take a f=1/(2*T) and a 5ms trans and measure vmax and vmin
anonymous
 3 years ago
answers !!!! qs 6 a) and b) L/(rw+rl) c and d) go to sandbox, make the circuit, take a f=1/(2*T) and a 5ms trans and measure vmax and vmin

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0thats correct aparna! now can u put a transient anlalysis graph pic here?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0aparna,do 1 thing,attach ur file showing transient analysis and then tell , where is vmax and where is vmin, i mean at what time do you measure them?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0@jason10 , i am attaching my transiant analysis , kindly now tell me the answer for last two parts from these graphs.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0capture 3 n4 r my values n i got it right

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0@jason10 , i have attached my file , can u tell me the answer for last two parts ????

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0@chaand.i for vmin u need to place the pointer a the min value i.e at 2ms(ur snap) n for max u need to place it at max peak value

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0@aparna.b , what is the stop time we need to set ? is that 5ms always ?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I checked two points of tran and my vmin value became bigger than vmax, it's ok?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0it ur wish. we can use even 10ms. but time time u choose must be very small n in ms

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0@aparna.b , my vmin = 42.22m and vmax = 5.925 .. is it ook ?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0@fatdrfrog vmin will be smaller than vmax. i think u calculated as V. its not V its mV

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0@chaand.i i think they r ryt.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0but @aparna.b , i am getting confused that how vmin can be 42.22m ?? :/

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0vmin is the min voltage across resistor. n if u point ur marker at min value u get dat

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0y is it that sum r getting it ryt n sum r getting it wrong?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0i dunno. but wat method i did is right.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0@jason10 am I right please check i am left with last check. i got part c as 4.32 and part d as 0.67 please tell me the answer i got 1st two green ticks, last two left.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0V0=5V, T=1ms, Rw=1Ω, Lw=1mH and RL=1Ω. vmax = ???? vmin = 0.67 4.308 and 4.328 are wrong, and I have only one check

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0@chaand.i I have the following values :V0=10V, T=0.5ms, Rw=1Ω, Lw=0.5mH and RL=4Ω.. i have a=0.1, b=0.1, c= 7.942. still having problems with d.
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