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jason10
Group Title
answers !!!!
qs 6
a) and b) L/(rw+rl)
c and d) go to sandbox, make the circuit, take a f=1/(2*T) and a 5ms trans and measure vmax and vmin
 one year ago
 one year ago
jason10 Group Title
answers !!!! qs 6 a) and b) L/(rw+rl) c and d) go to sandbox, make the circuit, take a f=1/(2*T) and a 5ms trans and measure vmax and vmin
 one year ago
 one year ago

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aparna.b Group TitleBest ResponseYou've already chosen the best response.0
@chaand.i check dis.
 one year ago

jason10 Group TitleBest ResponseYou've already chosen the best response.1
thats correct aparna! now can u put a transient anlalysis graph pic here?
 one year ago

jason10 Group TitleBest ResponseYou've already chosen the best response.1
aparna,do 1 thing,attach ur file showing transient analysis and then tell , where is vmax and where is vmin, i mean at what time do you measure them?
 one year ago

aparna.b Group TitleBest ResponseYou've already chosen the best response.0
this is v min
 one year ago

chaand.i Group TitleBest ResponseYou've already chosen the best response.0
@jason10 , i am attaching my transiant analysis , kindly now tell me the answer for last two parts from these graphs.
 one year ago

aparna.b Group TitleBest ResponseYou've already chosen the best response.0
capture 3 n4 r my values n i got it right
 one year ago

chaand.i Group TitleBest ResponseYou've already chosen the best response.0
@jason10 , i have attached my file , can u tell me the answer for last two parts ????
 one year ago

aparna.b Group TitleBest ResponseYou've already chosen the best response.0
@chaand.i for vmin u need to place the pointer a the min value i.e at 2ms(ur snap) n for max u need to place it at max peak value
 one year ago

chaand.i Group TitleBest ResponseYou've already chosen the best response.0
@aparna.b , what is the stop time we need to set ? is that 5ms always ?
 one year ago

fatdrfrog Group TitleBest ResponseYou've already chosen the best response.0
I checked two points of tran and my vmin value became bigger than vmax, it's ok?
 one year ago

aparna.b Group TitleBest ResponseYou've already chosen the best response.0
it ur wish. we can use even 10ms. but time time u choose must be very small n in ms
 one year ago

chaand.i Group TitleBest ResponseYou've already chosen the best response.0
@aparna.b , my vmin = 42.22m and vmax = 5.925 .. is it ook ?
 one year ago

aparna.b Group TitleBest ResponseYou've already chosen the best response.0
@fatdrfrog vmin will be smaller than vmax. i think u calculated as V. its not V its mV
 one year ago

aparna.b Group TitleBest ResponseYou've already chosen the best response.0
@chaand.i i think they r ryt.
 one year ago

chaand.i Group TitleBest ResponseYou've already chosen the best response.0
but @aparna.b , i am getting confused that how vmin can be 42.22m ?? :/
 one year ago

aparna.b Group TitleBest ResponseYou've already chosen the best response.0
vmin is the min voltage across resistor. n if u point ur marker at min value u get dat
 one year ago

jason10 Group TitleBest ResponseYou've already chosen the best response.1
y is it that sum r getting it ryt n sum r getting it wrong?
 one year ago

aparna.b Group TitleBest ResponseYou've already chosen the best response.0
i dunno. but wat method i did is right.
 one year ago

chiragsala Group TitleBest ResponseYou've already chosen the best response.0
@jason10 am I right please check i am left with last check. i got part c as 4.32 and part d as 0.67 please tell me the answer i got 1st two green ticks, last two left.
 one year ago

brunofornari Group TitleBest ResponseYou've already chosen the best response.0
V0=5V, T=1ms, Rw=1Ω, Lw=1mH and RL=1Ω. vmax = ???? vmin = 0.67 4.308 and 4.328 are wrong, and I have only one check
 one year ago

malchiva Group TitleBest ResponseYou've already chosen the best response.0
@chaand.i I have the following values :V0=10V, T=0.5ms, Rw=1Ω, Lw=0.5mH and RL=4Ω.. i have a=0.1, b=0.1, c= 7.942. still having problems with d.
 one year ago

malchiva Group TitleBest ResponseYou've already chosen the best response.0
for question 6
 one year ago
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